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Paraphin [41]
3 years ago
6

Find the equation of the form y=ax²+bx+c whose graph passes through the points (1,6), (3, 20), and (−2,15).

Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

Step-by-step explanation:

given ,

equation y=ax²+bx+c

passing through points (1,6), (3, 20), and (−2,15).

then these points will satisfy the equation

at (1,6)

y  = a x²+b x+c

6 = a(1)² + b (1) + c

a + b + c = 6------(1)

at (3 , 20)

y  = a x²+b x+c

20 = a(3)² + b (3) + c

9 a + 3 b + c = 20------(2)

at (−2,15)

y  = a x²+b x+c

15 = a(-2)² + b (-2) + c

4 a -2 b + c = 15------(3)

solving equation (1),(2) and (3)

a = 6 - b - c

9 (6 - b - c)+ 3 b + c = 20

6 b + 7 c = 34-------(4)

4 (6 - b - c) -2 b + c = 15

2 b + c = 3----------(5)

on solving equation (4) and (5)

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

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Which kind of function best models the data in the table? Graph the data and write an equation to model the data. x y 0 –2 1 –3
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Let

A (0,-2) B (1,-3) C (2,-4) D ( 3,-5) E (4,-6)


using a graph tool

see the attached figure N 1


case a) exponential

y=3^{x} -2

see the attached figure N 2


case b) quadratic

y=x^{2} -2

see the attached figure N 3


case c) linear

y=-x-2

see the attached figure N 4


case d) linear

y=x-2

see the attached figure N 5


therefore


the answer is

the case c) linear

y=-x-2











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Find the LCM of 18 and 45 using prime factorizations. ​
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Answer:

The L.C.M. of 18 and 45 is 90.

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Jada made 8 cups of blueberry jam and divided the jam equally among 6 containers. How much jam went in each container?
Greeley [361]

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I am really confused about this question for math.. any help would be really appreciated:
Elina [12.6K]

y= (\frac 1 4 )^x

A reflection about the x axis, about y=0, is the mapping (x',y')=(x,-y) so

y'= -y = - (\frac 1 4)^{x'}

A dilation of 2 is the mapping (x'',y'')=(2x', 2y')

So

x'=x''/2, y'=y''/2

y''/2= - (\frac 1 4)^{x''/2}

y'' =  - 2((\frac 1 4)^{1/2})^{x''}

y''= - 2(\frac 1 2)^{x''}

We can rewrite that without the primes and combine the powers of 2.

y =  - 2^{1-x}

Let's graph these and see if we're close,

Plot y= (1/4)^x, y= - (1/4)^{x}, y = - 2^{1-x}

6 0
3 years ago
Find the equation of the line through ( - 10, - 8) that is perpendicular to the line through (10,6), (5,5).
Furkat [3]

Answer:

y=-5x-58

Step-by-step explanation:

The equation of a line in slope-intercept form is y=mx+b where m is the slope and b is the y-intercept.

Perpendicular lines have opposite reciprocal slopes.

Anyways we need to find the slope of the line going through (10,6) and (5,5).

To find the slope, we are going to line up the points vertically and subtract vertically, then put 2nd difference over 1st difference. Like so:

 (  10   ,   6)

- (   5   ,   5)

------------------

    5         1

So the slope of the line through (10,6) and (5,5) is 1/5.

The slope of a line that is perpendicular will be the opposite reciprocal of 1/5.

The opposite reciprocal of 1/5 is -5.

The line we are looking for is y=-5x+b where we need to find the y-intercept b.

y=-5x+b goes through (-10,-8)

So we can use (x,y)=(-10,-8) to find b in y=-5x+b.

y=-5x+b with (x,y)=(-10,-8)

-8=-5(-10)+b

-8=50+b

Subtract 50 on both sides:

-8-50=b

-58=b

So the equation is y=-5x-58

4 0
3 years ago
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