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Damm [24]
3 years ago
9

Solve 8x − 2(x + 1) = 7x + 8. (5 points) 6 −6 −10 10

Mathematics
1 answer:
sesenic [268]3 years ago
7 0
First, simplify the equation.
8x - 2x - 2 = 7x + 8
Now subtract 8 on both sides to get rid of the one on the right side.
8x - 2x - 10 = 7x
Solve the left side.
6x - 10 = 7x
Subtract 6x from both sides.
-20 = x
Therefore, x = -20.
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y=12

Step-by-step explanation:

Lets write out the equation so it easy to work with.

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Use algebra to solve 3x+4 = 1/x<br> The exact solutions are x=<br> Х
skad [1K]

Answer:

Ignore the A before the ±, it wouldn't let me type it correctly.

x=\frac{2±\sqrt{7}  }{3}

Step-by-step explanation:

3x + 4 = 1 ÷ x

3x + 4 - 4 = 1 ÷ x - 4

3x = 1 ÷ x - 4

3x=\frac{1}{x} +\frac{x(-4)}{x}

3x=\frac{1+x(-4)}{x}

3x=\frac{1-4x}{x}

x(3x)=x(\frac{1-4x}{x})

x · 3x = - 4x + 1

3x² = - 4x + 1

3x² - (- 4x + 1) = 0

3x² + 4x - 1 = 0

Ignore the A before the ±, it wouldn't let me type it correctly.

x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

a = 3

b = 4

c = - 1

x=\frac{-4±\sqrt{4^{2}-4((3)(-1)) } }{2(3)}

x=\frac{-4±\sqrt{16-4((3)(-1)) } }{2(3)}

x=\frac{-4±\sqrt{16+12 } }{2(3)}

x=\frac{-4±\sqrt{28 } }{2(3)}

x=\frac{-4±\sqrt{(2)(14) } }{2(3)}

x=\frac{-4±\sqrt{(2)(2)(7) } }{2(3)}

x=\frac{-4±\sqrt{2 } \sqrt{2}\sqrt{7}  }{2(3)}

x=\frac{-4±2\sqrt{7}  }{2(3)}

x=\frac{-4±2\sqrt{7}  }{6}

Two separate equations

x=\frac{-4+2\sqrt{7}  }{6}

x=\frac{2+\sqrt{7}  }{3}

x=\frac{-4-2\sqrt{7}  }{6}

x=\frac{2-\sqrt{7}  }{3}

7 0
3 years ago
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