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wolverine [178]
3 years ago
5

Please help ill give brainiest

Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0

Answer:

give it

Step-by-step explanation:

the answer is m=1/4

Aloiza [94]3 years ago
7 0
The answer is no solution
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Write the equation of the line that passes through (0,5) and is perpendicular to the line x = 3.
Alona [7]

Answer:

(0,5)x3=(15,5)

Step-by-step explanation:

3 0
2 years ago
Solve for w.<br><br> 5w + 9z = 2z + 3w<br><br> w = z<br> w = z<br> w = –2z<br> w = –7z
Semenov [28]

5w + 9z = 2z + 3w

Move terms with w to the left - subtract 3w from both sides

2w + 9z = 2z

Subtract 9z from both sides

2w = -7z

Divide both sides by 2

w = \frac{-7}{2}z

6 0
3 years ago
Darren drank 2 liters of water.How much millilliters of water did he drank
Elodia [21]
1 liter = 1,000 ML
2 X 1,000 = 2,000 ML
2,000 milliliter is your answer
4 0
3 years ago
Determine if the function is one-to-one.<br><br>​
olya-2409 [2.1K]

Answer:

No

Step-by-step explanation:

From what I saw on google for what "one to one" means, It's basically meaning that the bottom of that quadratic function is at point (0 , 0) and hits both (-1 , 1) and (1 , 1) on the graph.

4 0
3 years ago
The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac
olya-2409 [2.1K]

Answer:

a) \frac{74}{10025}

b) \frac{3x-2}{x(8x+1)}

c) \frac{-24x^2+32x-2}{(8x^2+x)^2}

Step-by-step explanation:

For total cost function c(x), average cost is given by \frac{c(x)}{x} i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., \left ( \frac{c(x)}{x} \right )'

Given:c(x)=\frac{3x-2}{8x+1}

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

a)

At x = 50 units,

\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}

b)

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

c)

Marginal average cost:

Differentiate average cost with respect to x

Take f=3x-2\,,\,g=8x^2+x

using quotient rule, \left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}

Therefore,

\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}

3 0
3 years ago
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