We have a "rectangular" double loop, meaning that both loops go to completion.
So there are 3*4=12 executions of t:=t+ij.
Assuming two operatiions per execution of the innermost loop, (i.e. ignoring the implied additions in increment of subscripts), we have 12*2=24 operations in all.
Here the number of operations (+ or *) is exactly known (=24).
Big-O estimates are used for cases with a varying scale of operations, governed by a variable (usually n) to indicate the sensitivity of the number of operations relative to a change in the size of n.
Here we do not have a scale, nor n is defined. The number of operations is constant and known at 24. So a variable is required to find the big-O estimate.
Answer:
<u>The correct answer is 58 1/2 feet. See below to understand the difference of both methods.</u>
Step-by-step explanation:
1. Let's review the information provided to us for solving the question using both methods:
Area of each student = 4 1/2 square feet
Number of students = 13
2. Let's use the first method to solve the question:
4 1/2 = 9/2 (Improper fraction because the numerator, 9 is bigger than the denominator, 2)
9/2 * 13 = 117/2
<u>117/2 = 58 1/2 square feet</u>
3. Let's use the second method to solve the question:
4 1/2 = 4 + 1/2 (Using addition to rewrite the fraction)
(4 + 1/2) * 13 = (4 * 13) + (1/2 * 13) (Distributive property of the multiplication)
(4 * 13) + (1/2 * 13) = 52 + 13/2 = 52 + 6 1/2
<u>52 + 6 1/2 = 58 1/2 square feet</u>
I'm guessing Q lol. I hope that's helpful.
Answer:
25
Step-by-step explanation:
so you replace all the x's with 15 and it becomes
2×15-5
2×15=30
30-5=25
Answer:
C. 8 units right and 5 units down
Step-by-step explanation:
since it's only a translation, take one point as an example. lets say the bottom right point on trapezoid P is point A, and the translated point on P' is A'. the coordinates of A are (-3,2) while the coordinates of A' are (5,-3). (-3+x,2+y)=(5,-3). -3+x=5, x=8; 2+y=-3, y=-5
