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Vadim26 [7]
3 years ago
6

Can 5/9 be simplified

Mathematics
2 answers:
asambeis [7]3 years ago
7 0
To a decimal you can round it down to .5 but if its a fraction no.
earnstyle [38]3 years ago
7 0
No, 5/9 is in it's exact form
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What is the sum of 2 1/3, 3 5/6 and 6 2/3
Andreas93 [3]
2 1/3+ 3 5/6+ 6 2/3
= 7/3+ 23/6+ 20/3
= 14/6+ 23/6+ 40/6
= 77/6
= 12 5/6

The final answer is 12 5/6~
5 0
3 years ago
A Web music store offers two versions of a popular song. The size of the standard version is
kicyunya [14]
2.4x+4.7(4x)=5936
Solve for x
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5 0
3 years ago
Barb solved the following equation: 4(3x – 12) = 5(2x + 6)
katrin2010 [14]

Answer:

4(3 * 39 – 12) = 5(2 * 39 + 6)

x = 39


Step-by-step explanation:

4(3x – 12) = 5(2x + 6)

(12x - 48) = (10x + 30)

12x - 10x = 30 + 48

2x = 78

2x/2 = x

78/2 = 39

x = 39

No Prob :)

5 0
3 years ago
Read 2 more answers
A painting is 24 in. Wide by 32in. Long. The width of a postcard reductions of the painting is 3in. How long is the postcard
s344n2d4d5 [400]

Answer:

4 inches.

Step-by-step explanation:

24 32

---- = -----

3 x

Cross multiply.

24x = (32)(3) = 96.

96 / 24 = 4.

Hope this helped and good luck! (:

7 0
3 years ago
What is the area of the parllelogtam shown below
Umnica [9.8K]
<h3>Answer: 16 square units</h3>

Let x be the height of the parallelogram. Right now it's unknown, but we can solve for it using the pythagorean theorem. Focus on the right triangle. It has legs a = 3 and b = x, with hypotenuse c = 5

a^2 + b^2 = c^2

3^2 + x^2 = 5^2

9 + x^2 = 25

x^2 = 25-9

x^2 = 16

x = sqrt(16)

x = 4

This is a 3-4-5 right triangle.

The height of the parallelogram is 4 units.

We have enough info to find the area of the parallelogram

Area of parallelogram = base*height

Area of parallelogram = 4*4

Area of parallelogram = 16 square units

Coincidentally, the base and height are the same, which isn't always going to be the case. The base is visually shown as the '4' in the diagram. The height is the dashed line, which also happens to be 4 units long.

6 0
3 years ago
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