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zlopas [31]
2 years ago
9

HELPPP PLEASEEEE

Mathematics
1 answer:
Kryger [21]2 years ago
3 0

Answer:

I think glide reflection

Step-by-step explanation:

a certain video on yt had explained the examples of similar look alike this picture

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I need answer for this quick please
Anna007 [38]

Answer:

- 6

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 1, 4 ] , then

f(b) = f(4) = 4³ - 6(4)² - 4 = 64 - 96 - 4 = - 36

f(a) = f(- 1) = (- 1)³ - 6(- 1)² - (- 1) = - 1 - 6 + 1 = - 6 , then

average rate of change = \frac{-36-(-6)}{4-(-1)} = \frac{-36+6}{4+1} = \frac{-30}{5} = - 6

5 0
3 years ago
Doris uses 8square pieces of fabric to make one scarf. Each side of a square piece of fabric is 1/4 foot in length. Doris can bu
Semmy [17]
Scarf area is 8 small fabric area
8 x 0.25 x 0.25 =0.5.
7 scarf area would be
7 x 0.5 = 3.5
new fabric (large ) area is
2 x 0.25 = 0.5
7 scarf area divide by new fabric area
3.5 divide by 0.5 = 7 large pieces
4 0
3 years ago
What is the reciprocal of 1 and 1/9
podryga [215]

Answer:

reciprocal of 1 is 1 and 1/9 is 9.

6 0
3 years ago
A + b − _____ = a<br> help :)
ss7ja [257]

Step-by-step explanation:

Subtract a from both sides

a-a+b-___=a-a

b-__=0

b=___

answer:b

Hope that helps :)

6 0
3 years ago
Read 2 more answers
I need help ASAP. Thank you :)
kvasek [131]

m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠ABF + m∠CBF = 180°

116° + m∠CBF = 180°

m∠CBF = 64°

If CD || BE, then CD || BF.

Hence CD || BE and BE || FD.

Therefore BFCD is a parallelogam.

<em>In parallelogram, Adjacent angles form a linear pair.</em>

m∠CBF + m∠BFD = 180°

64° + m∠BFD = 180°

m∠BFD = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

m∠DFE = 64°

we know that DE ≅ DF.

<em>In triangle, angles opposite to equal sides are equal.</em>

m∠DFE = m∠DEF

m∠DEF = 64°

<em>sum of all the angles of a triangle = 180°</em>

m∠DFE + m∠DEF + m∠FDE = 180°

64° + 64° + m∠FDE = 180°

m∠FDE = 52°

8 0
3 years ago
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