All categories

3 years ago

Original price: $89.00; Markdown: 33%

Mathematics

2 answers:

RSB [31]3 years ago

7 0

Vikki [24]3 years ago

6 0

The new price is 59.63

You might be interested in

Tony separates a number of paintbrushes, x, into 3 equally sized groups. He claims that this is the same as making a group 1/3 t

DochEvi [55]

Answer:

Size of each group = $\frac{x}{3}$

Step-by-step explanation:

Total number of paint brushes = x

Since each the three groups are equally sized, to get the number of paintbrushes in a group, we will have to divide the total number of paint brushes by 3

∴ We have, number of paint brushes in a group = $\frac{Total number of paintbrushes}{3}\\$

= $\frac{x}{3}$

this is also the same thing as saying $\frac{1}{3}$ × $\frac{x}{1}$

This shows that the size of the new group is the same as $\frac{1}{3}$ the size of the original group

4 0

3 years ago

Braydon is mixing cement for a large patio.

kakasveta [241]

I believe 15 would be the correct answer

4 0

3 years ago

Read 2 more answers

A stone which is dropped into a dry well hits the bottom in 2.2s how deep is the well. take g=10m/s

Papessa [141]

Answer:

23.7m

Step-by-step explanation:

Given parameters:

Time taken = 2.2s

Acceleration due to gravity = 10m/s

Unknown:

Depth of the well = ?

Solution:

To solve this problem, we simply apply one of the motion equations;

S = ut + $\frac{1}{2}$ gt²

where S = depth of the well

u = initial velocity

t = time taken

g = acceleration due to gravity

Input the parameters and solve for S;

Note initial velocity = 0;

S = $\frac{1}{2}$ x 9.8 x 2.2²

S = 23.7m

3 0

3 years ago

Please help me. Any help is greatly appreciated

iragen [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Each of 16 students measured the circumference of a tennis ball by four different methods, which were:Method A: Estimate the cir

lys-0071 [83]

Answer:

a) $\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

b) $Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

c) $\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

Step-by-step explanation:

Data given

Assuming the following data:

Method A: 18.0, 18.0, 18.0, 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0,25.0,26.0,26.4

Method B: 18.8, 18.9, 18.9, 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0, 22.0,22.0,23.6

Method C: 20.2, 20.5, 20.5, 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5,21.5,21.5,21.6

Method D: 20.0, 20.0, 20.0,-20.0, 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5, 21.6, 22.1,22.3.

Part a

The sample mean is defined as:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

If we apply this formula for the four methods we got:

$\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

Part b

Since the total number of points for each method is 16 and this is an even number we need to calculate the median as the average between the 8th and the 9th position of the data ordered from the smallest to the largest. If we do this we have that:

$Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

Part c

The trimmed mean by 20% means that we need to calculate removing the 20% from each of the tails, the 20% of 16 is 3.2, so we need to remove 3 observations from both ends of the data like this:

Method A: 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0

Method B: 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0

Method C: 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5

Method D: 20.0 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5.

If we calculate the mean for each method we got:

$\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

3 0

3 years ago