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2 years ago

What is the answer???

Mathematics

2 answers:

iren2701 [21]2 years ago

7 0

The answer is b.................

frez [133]2 years ago

4 0

B will b the answer that's the only answer yuh can get is b

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Looking for right triangle side a is 1 inch long,and side b is 2 inches long. What is the length of side c?

Sergeeva-Olga [200]

Answer:

$\sqrt{5}$

Step-by-step explanation:

$a^{2} + b^{2} = c^{2}$

In this situation a = 1, b = 2

$1^{2} + 2^{2} = c^{2}$

1 + 4 = $c^{2}$

5 = $c^{2}$

c = $\sqrt{5}$

This is an important mathematical theorem to know. It's called the Pythagorean Theorem.

3 0

2 years ago

Please help :(( ive been stuck for a while and im super late

Degger [83]

Answer:

-5^11

Step-by-step explanation:

3 0

2 years ago

Christopher estimates it will take him half an hour to complete his math homework. He is able to complete it in 25 minutes. What

marin [14]

Answer:

The percent error in his estimate is<u> 16.67%</u>.

Step-by-step explanation:

Given:

Christopher estimates it will take him half an hour to complete his math homework.

He is able to complete it in 25 minutes.

Now, to find the percent error in his estimate.

Time estimates of completing homework = 30 minutes.

Time actual taken to complete homework = 25 minutes.

Error in estimate = Time estimates of completing homework - Time actual taken to complete homework.

Error in estimate = 30 minutes - 25 minutes.

Error in estimate = 5 minutes.

Now, to get the percent error:

$Percent\ error =\frac{Error\ in\ estimate}{Time\ estimates\ of\ completing\ homework} \times 100.$

$Percent\ error=\frac{5}{30} \times 100$

$Percent\ error=\frac{500}{30}$

$Percent\ error=16.67\%.$

Therefore, the percent error in his estimate is 16.67%.

6 0

3 years ago

How many minutes would you have to exercise each day to have a resting heart rate of 60 beats per minute?

Svetradugi [14.3K]

Answer:

i think 2-3 min.

Step-by-step explanation: i wish it's help u

5 0

2 years ago

According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var

-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}$

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.9

11.2

11.5

11.8

n=10(even)

$Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7$

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}$

Standard deviation : $\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}$

Standard deviation :0.89916

8.3

,10.3

,10.5

,10.6

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5$

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2$

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range : $(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)$

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

3 0

2 years ago