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maks197457 [2]
3 years ago
10

Determine if the two triangles are congruent. If they are, state how you know.

Mathematics
2 answers:
Crazy boy [7]3 years ago
8 0
C.AAS
Because vertical angles are congruent.
Alona [7]3 years ago
3 0

Answer:

D) SAS

Step-by-step explanation:

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Hey, I was just wondering what is 1/3 + 1/2?
cestrela7 [59]

Answer:

5/6

Step-by-step explanation:

1/3 x 2/2 = 2/6

1/2 x 3/3 = 3/6

2/6 + 3/6 = 5/6

3 0
3 years ago
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Use the following prompt to answer the next 6 questions. Suppose we want to test the color distribution claim on the M&M’s w
vitfil [10]

Answer:

The claim on the M&M’s website is not true.

Step-by-step explanation:

A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

<em>H</em>₀: The observed frequencies are same as the expected frequencies.

<em>Hₐ</em>: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}

Here,

O_{i} = Observed frequencies

E_{i}=N\times p_{i} = Expected frequency.

The chi-square test statistic value is, 14.433.

The degrees of freedom is:

df = <em>k</em> - 1 = 6 - 1 = 5

Compute the <em>p</em>-value as follows:

p-value=P(\chi^{2}_{k-1} >14.433) =P(\chi^{2}_{5} >14.433) =0.013

*Use a Chi-square table.

The significance level is, <em>α</em> = 0.05.

p-value = 0.013 < <em>α</em> = 0.05.

So, the null hypothesis will be rejected at 5% significance level.

Thus, concluding that the claim on the M&M’s website is not true.

6 0
3 years ago
HELP PLEASE :) <br> option for A= <br> Andrews class and 6<br> I=<br> Lauren's class and 6
Natali [406]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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participar de uma maratona um atleta inicia um treinamento mensal, em que corre todo dia e sempre 2 minutos a mais do que correu
AleksandrR [38]

Answer:

59 minutes

Step-by-step explanation:

In the table of values ​​it is observed that for each day of training 2 minutes are increasing and that day 1 begins with 5 minutes of training , so

y(x)=2\frac{min}{d}(x)+3min, where x= evaluation day

we have to for the day 28

y(28)=2\frac{min}{d}(28d)+3min=59min

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4 years ago
PLEASE HELP!!
Rom4ik [11]
Angle 45° + 45° + 90°
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