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DIA [1.3K]
3 years ago
8

Please help me please

Mathematics
2 answers:
pashok25 [27]3 years ago
7 0
{3a}^{2} + 4(2b + c)

When a = 2, b = 3 and c = 5,

3( {2}^{2} ) + 4(2(3) + 5) = 56

Hope this helps :)
jeka57 [31]3 years ago
6 0

Answer:

56

Step-by-step explanation:

3 * 2 * 2 = 12

4[(2*3) + 5] = 4(6+5) = 4(11) = 44

12+44 = 56

Hope this helps! Have a great day!

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Step-by-step explanation:

The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

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In this question:

12 resistors, which means that N = 12

3 defective, which means that k = 3

4 are selected, which means that n = 4

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