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4 years ago

Who can use scientific inquiry and what does it involve?

1 answer:

4 0

Anyone can use it it involves asking questions.observing and and inferrring experimenting and collecting datafinding evidence drawing conclusions

You might be interested in

Food dye allergies have increased in recent years. One study calculated that each 47.9 g serving of M&M's candy contains 240

77julia77 [94]

Answer:

Mass percent of food dyes = 0.0616%

Explanation:

Given data:

Mass of candy = 47.9 g

Calories = 240

Mass of fat = 10 g

Mass of carbohydrate = 34 g

Mass of protein = 2 g

Mass of food dyes = 29.5 mg

Mass percent of food dyes = ?

Solution:

First of all we will convert the mg into g.

Mass of food dyes = 29.5 mg × 1g /1000 mg = 0.0295 g

Mass percent of food dyes = mass of food dyes / total mass× 100

Now we will put the values.

Mass percent of food dyes = 0.0295 g / 47.9 g × 100

Mass percent of food dyes = 0.000616 × 100

Mass percent of food dyes = 0.0616%

3 0

4 years ago

Dinitrogen tetraoxide is a colorless gas at room temperature. It can dissociate into nitrogen dioxide, which is a reddish brown

Alenkinab [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The calculation and filling of the table based on the ratio indicated by the column is shown on the second uploaded image

1 This is True

2 This is False

3 This is False

4 This is True

5 This is True

Explanation:

Based on your calculations, indicate whether each statement is True (T) or False (F):

Considering the first statement

Looking at the question we can see that the first statement is TRUE this because all the three experiment have different initial concentration (3.5,3.0 & 2.6)

Considering the second statement

Looking at table we can see that the second statement is FALSE because

the ratio value of [NO2]/ [N2O4] in all three experiment have different value 1.4 , 1.5 & 1.7 is not a constant value.

Considering the Third statement

Looking at the table we can see that the third statement is FALSE this is because the ratio value of 2[NO2]/ [N2O4] in all three experiment have different value 2.7, 3.0 & 3.3 is not a constant value.

Considering the Fourth statement

Looking at table we can see that the fourth statement is TRUE this is because the ratio value of $[NO2]^{2}/ [N2O4]$ in all three experiment have same value 3.9, 3.9 & 3.9 is a constant value.

Considering the Fifth statement

Looking at table we can see that the fifth statement is TRUE this is because

each having different set of Equilibrium concentration

3 0

4 years ago

Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Cr2 ] = 0.892 M and [Fe2 ] = 0.0150

Effectus [21]

Given:

Concentration of Cr2+ = 0.892 M

Concentration of Fe2+ = 0.0150 M

To determine:

The cell potential, Ecell

Explanation:

The half cell reactions for the given cell are:

Anode: Oxidation

Cr(s) ↔ Cr2+(aq) + 2e⁻ E⁰ = -0.91 V

Cathode: Reduction

Fe2+ (aq) + 2e⁻ ↔ Fe (s) E⁰ = -0.44 V

------------------------------------------

Net reaction: Cr(s) + Fe2+(aq) ↔ Cr2+(aq) + Fe(s)

E°cell = E°cathode - E°anode = -0.44 - (-0.91) = 0.47 V

The cell potential can be deduced from the Nernst equation as follows:

Ecell = E°cell - (0.0591/n)log[Cr2+]/[Fe2+]

Here, n = number of electrons = 2

Ecell = 0.47 - 0.0591/2 * log[0.892]/[0.0150] = 0.418 V

Ans: The cell potential is 0.418 V

8 0

3 years ago

Read 2 more answers

A 850.0 mL cylinder containing B2H6 at a pressure of 0.900 atm is connected by a valve to 1000 mL cylinder containing C6H6 at 60

8_murik_8 [283]

Answer:

The partial pressure of $C_6H_6$ when the valve is opened is 328.6 Torr.

Explanation:

Initial pressure of the $C_6H_6=P_1=608.0 Torr$

Initial volume of the $C_6H_6=V_1=1000 mL$

After opening the valve :

Final pressure or partail pressure of the $C_6H_6=P_2$

Final volume of the $C_6H_6=V_2=1000 mL+850.0 mL=1850.0 mL$

$P_1V_1=P_2V_2$ ( Boyle's law)

$P_2=\frac{608.0 Torr \times 1000 mL}{1850.0 mL}=328.6 Torr$

The partial pressure of $C_6H_6$ when the valve is opened is 328.6 Torr.

4 0

3 years ago

What is the ph of a 0.001 62 m naoh solution?

marin [14]

The answer
first of all, we should know that NaOH is a strong base. For such a product, the conentration of the OH - is equivalent to the concentration of the NaOH itself.
that means:
[ OH -] = [ NaOH] =0.001 62
and for a strong basis, pH can be calculated as pH = 14 + log [ OH -]
first we compute log [ OH -] :
log [ OH -] = log (0.001 62)= -2.79

finally pH = 14 -2.79 = 11.20

4 0

3 years ago