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2 years ago

What is the ph of a 0.001 62 m naoh solution?

1 answer:

4 0

The answer
first of all, we should know that NaOH is a strong base. For such a product, the conentration of the OH - is equivalent to the concentration of the NaOH itself.
that means:
[ OH -] = [ NaOH] =<span>0.001 62
and for a strong basis, pH can be calculated as pH = 14 + log </span>[ OH -]
first we compute log [ OH -] :
log [ OH -] = log (0.001 62)= -2.79

finally pH = 14 -2.79 = 11.20

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Polysaccharides, that allow sugar to polymerize

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How many liters of o2 do you have if you have 5.8 moles of o2

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2 years ago

What occurs in a chemical reaction? ( No chemical bonds are broken. , Reactants break bonds and reform the same bonds., Reactant

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3 years ago

Read 2 more answers

A 0.15 m solution of chloroacetic acid has a ph of 1.86. What is the value of ka for this acid?

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Answer: $1.67\times 10^{-3}$

Explanation:

$ClCH_2COOH\rightarrow ClCH_2COO^-+H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Given: c = 0.15 M

pH = 1.86

$K_a$ = ?

Putting in the values we get:

Also $pH=-log[H^+]$

$1.86=-log[H^+]$

$[H^+]=0.01$

$[H^+]=c\times \alpha$

$0.01=0.15\times \alpha$

$\alpha=0.06$

As $[H^+]=[ClCH_2COO^-]=0.01$

$K_a=\frac{(0.01)^2}{(0.15-0.15\times 0.06)}$

$K_a=1.67\times 10^{-3]$

Thus the vale of $K_a$ for the acid is $1.67\times 10^{-3}$

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3 years ago

Which choice gives the correct oxidation numbers for all three elements in rb2so3 in the order that the elements are shown in th

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<h3>Answer:</h3>

Rb = + 1

S = + 4

O = - 2

<h3>Explanation:</h3>

Oxidation states of the elements were calculated keeping in mind the basic rules of assigning oxidation states which included assignment of +1 charge to first group elements i.e. Rubidium (Rb) and assignment of -2 charge to Oxygen atom. Then the oxidation state of Sulfur was calculated as follow,

Rb₂ + S + O₃ = 0

Above zero (0) means that the overall molecule is neutral.

Putting values of Rb and O,

(+1)₂ + S + (-2)₃ = 0

(+2) + S + (-6) = 0

+2 + S - 6 = 0

S - 6 = -2

S = -2 + 6

S = + 4

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3 years ago