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ad-work [718]
3 years ago
12

What is the ph of a 0.001 62 m naoh solution?

Chemistry
1 answer:
marin [14]3 years ago
4 0
The answer 
first of all, we should know that NaOH is a strong base. For such a product, the conentration of the OH -  is equivalent to the concentration of the NaOH itself.
that means:
[ OH -] = [ NaOH] =<span>0.001 62 
and for a strong basis, pH can be calculated as pH = 14 + log </span>[ OH -] 
first we compute log [ OH -] :
log [ OH -] = log (0.001 62)= -2.79

finally pH = 14 -2.79 = 11.20
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A hollow conductor is positively charged. A small uncharged metal ball is lowered by a silk thread (insulating material) through
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Explanation:

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Read 2 more answers
Find the mass of AlCl3 that is produced when 25.0 grams of Al2O3 react with excess HCl according to the following equation.
kondaur [170]

Answer:

Mass = 65.4 g

Explanation:

Given data:

Mass of Al₂O₃ = 25 g

Mass of AlCl₃ = ?

Solution:

Chemical equation:

Al₂O₃ + 6HCl  →   2AlCl₃ + 3H₂O

Number of moles of Al₂O₃:

Number of moles = mass/ molar mass

Number of moles = 25 g/  101.96 g/mol

Number of moles = 0.2452 mol

Now we will compare the moles of Al₂O₃  and AlCl₃.

                          Al₂O₃         :            AlCl₃

                              1             :               2

                             0.2452    :          2×0.2452 = 0.4904 mol

Mass of AlCl₃:

Mass = number of moles × molar mass

Mass = 0.4904 mol × 133.34 g/mol

Mass = 65.4 g

8 0
3 years ago
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