1) Calculate the number of moles of Cu SO4 . 5H20 by dividing the specified mass by the molar mass.
2) The ratio of production given by the equation is 1 mol of Cu SO4 . 5 H2O to 1 mol of Cu SO4=> 1:1, meaning that the number of moles of Cu SO4 produced is the same number of moles of Cu SO4.5H20 heated.
3) Finally mutiply the number of moles of Cu SO4 by its molar mass and there you have the mass of Cu SO4 produced.
Answer:
Periodic Law.
Explanation:
The Periodic Law states that the physical and chemical properties of the elements repeat in a systematic and predictable way when the elements are arranged in order of increasing atomic number.
Many of the properties are repeated at intervals.
When the elements are arranged correctly, the trends in element properties become apparent and can be used to make predictions about unknown or unfamiliar elements, simply based on their placement on the table.
Answer:
V = 44.83 L
Explanation:
Given data:
Mass of fluorine = 76 g
Temperature = 0°C (0°C + 273 = 273 K)
Pressure = 101.3 Kpa ( 101.3 / 101 = 1 atm)
Volume of fluorine = ?
Solution:
Number of moles of F = Mass/ molar mass
Number of moles = 76 g/ 38 g/mol
Number of moles = 2 mol
Volume of fluorine:
PV = nRT
V = nRT/ P
V = 2 mol × 0.0821 atm. L/ mol. k × 273 k / 1 atm
V = 44.83 L. atm / 1 atm
V = 44.83 L
Answer:
0.0734 grams LiOH
Explanation:
The molarity formula looks like this:
Molarity (M) = moles / volume (L)
You are given the molarity and volume (in mL). Therefore, you can plug these values into the equation and solve for moles (after you convert from mL to L).
25 mL / 1,000 = 0.025 L
0.125 M = moles / 0.025 L
(0.125 M) x (0.025 L) = moles
0.003125 = moles
After using the molarity formula, we know that 0.003125 moles LiOH are needed to satisfy these conditions. Now, we can convert this to grams using the molar mass of LiOH. This can be determined using the values from the periodic table. Remember to write your conversion in a way that allows for the units to cancel out.
Molar Mass (LiOH) = 6.941 g/mol + 16.00 g/mol + 1.008 g/mol
Molar Mass (LiOH) = 23.499 g/mol
0.003125 moles 23.499 g
------------------------ x ------------------- = 0.0734 grams LiOH
1 mole