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denpristay [2]
3 years ago
11

Food dye allergies have increased in recent years. One study calculated that each 47.9 g serving of M&M's candy contains 240

calories 10 g of fat, 34 g of carbohydrates , 2 g of proteinand 29.5 mg of food dyes. What is the mass percent of food dyes in the M &M's candy ?
A ) 0.0616%
B) 4.18%
C)20.9
D) 71.5 %
Chemistry
1 answer:
77julia77 [94]3 years ago
3 0

Answer:

Mass percent of food dyes  = 0.0616%

Explanation:

Given data:

Mass of candy = 47.9 g

Calories = 240

Mass of fat = 10 g

Mass of carbohydrate = 34 g

Mass of protein = 2 g

Mass of food dyes = 29.5 mg

Mass percent of food dyes = ?

Solution:

First of all we will convert the mg into g.

Mass of food dyes = 29.5 mg × 1g /1000 mg = 0.0295 g

Mass percent of food dyes  = mass of food dyes / total mass× 100

Now we will put the values.

Mass percent of food dyes  = 0.0295 g / 47.9 g × 100

Mass percent of food dyes  =  0.000616 × 100

Mass percent of food dyes  = 0.0616%

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Answer : The volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

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From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of NH_3

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Using ideal gas equation :

PV = nRT

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V = Volume of gas = ?

n = number of moles of gas = 2.37 moles

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 14.0^oC=273+14.0=287K

Putting values in above equation, we get:

0.989atm\times V=2.37mole\times (0.0821L.atm/mol.K)\times 287K

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As, 1 mole of HCl react with 1 mole of NH_4Cl

So, 2.07 mole of HCl react with 2.07 mole of NH_4Cl

Now we have to calculate the mass of NH_4Cl

\text{ Mass of }NH_4Cl=\text{ Moles of }NH_4Cl\times \text{ Molar mass of }NH_4Cl

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\text{ Mass of }NH_4Cl=(2.07moles)\times (53.5g/mole)=110.7g

Thus, the volume of the gas remaining is 56.5 liters.

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