which interaction of nature binds neutrons and protons into nuclei? A. strong B. weak C. electromagnetic D. gravitational

An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal inci

VikaD [51]

Answer:

572.3 nm

Explanation:

$n_{oil}$ = refractive index of the oil film = 1.48

$t_{oil}$ = thickness of the oil film = 290 nm

$\lambda$ = wavelength of the dominant color

m = order

Using the equation

$2 n_{oil} t_{oil} = (m + 0.5) \lambda$

For m = 0

$2 (1.48) (290) = (0 + 0.5) \lambda$

$\lambda$ = 1716.8 nm

For m = 1

$2 (1.48) (290) = (1 + 0.5) \lambda$

$\lambda$ = 572.3 nm

For m = 2

$2 (1.48) (290) = (2 + 0.5) \lambda$

$\lambda$ = 343.4 nm

Hence the dominant color wavelength is 572.3 nm

8 0

3 years ago

A section of a parallel-plate air waveguide with a plate separation of 7.11 mm is constructed to be used at 15 GHz as an evanesc

adell [148]

Answer:

the required minimum length of the attenuator is 3.71 cm

Explanation:

Given the data in the question;

we know that;

$f_{c_1$ = c / 2a

where f is frequency, c is the speed of light in air and a is the plate separation distance.

we know that speed of light c = 3 × 10⁸ m/s = 3 × 10¹⁰ cm/s

plate separation distance a = 7.11 mm = 0.0711 cm

so we substitute

$f_{c_1$ = 3 × 10¹⁰ / 2( 0.0711 )

$f_{c_1$ = 3 × 10¹⁰ cm/s / 0.1422 cm

$f_{c_1$ = 21.1 GHz which is larger than 15 GHz { TEM mode is only propagated along the wavelength }

Now, we determine the minimum wavelength required

Each non propagating mode is attenuated by at least 100 dB at 15 GHz

so

Attenuation constant TE₁ and TM₁ expression is;

∝₁ = 2πf/c × √( ( $f_{c_1$ / f)² - 1 )

so we substitute

∝₁ = ((2π × 15)/3 × 10⁸ m/s) × √( (21.1 / 15)² - 1 )

∝₁ = 3.1079 × 10⁻⁷

∝₁ = 310.79 np/m

Now, To find the minimum wavelength, lets consider the design constraint;

20log₁₀ $e^{-\alpha _1l_{min$ = -100dB

we substitute

20log₁₀ $e^{-(310.7np/m)l_{min$ = -100dB

$l_{min$ = 3.71 cm

Therefore, the required minimum length of the attenuator is 3.71 cm

6 0

2 years ago

If a 500-pound object is moved 200 feet how much work is being done?

Paha777 [63]

Answer:

D

Explanation:

Work = Distance x Mass

4 0

2 years ago

Which is the best example of Newton's First Law of Motion? A small, lightweight ball and a large, heavy ball are dropped off the

Marizza181 [45]

I believe the best example of Newton's First Law of motion would be the example or illustration with the basketball player. An object will move in a straight line or a given direction at a constant speed unless or until another force acts upon the object, causing a change in speed and or direction.

4 0

3 years ago

Read 2 more answers

How to measure the external diameter of a sphere

DanielleElmas [232]

Sphere is that the circular objects in the two dimensional space (1) circle
(2) disk. Two dimensional space is a set of points and the distance of that point,The two points of Sphere that length and center.
Sphere can constructed as the named of surface form circle about any diameter. circle is the special type of the revolution replacing the circle,
sphere is the distance r is the radius of the ball and circle is the center of mathematical ball,as the center and the radius of the sphere is to respectively.
The ball and sphere has not be maintained mathematical references as a solid references. A sphere of any radius is centered at the number of zero.

4 0

3 years ago