Answer:
The magnetic field in the center of the solenoid is 
.
Explanation:
Given that,
Length of solenoid = 0.425 m
Number of turns N = 950
Current I = 2.75 A
The magnetic field in the center of the solenoid is the product of the current , number of turns per unit length and permeability.
In mathematical form,
Where, 
N = number of turns
L = length
I = current
Now, The magnetic field
Put the value into the formula
Hence, The magnetic field in the center of the solenoid is .
The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value
Answer:
the magnitude of the magnetic force on the wire is 0.2298 N
Explanation:
Given the data in the question;
we know that, the magnitude of magnetic force is given as;
|F
| = I(
× 
)
given that
I = 2.6 A
= 0.17
= 0.52
so we substitute
|F | = 2.6( 0.17i" × 0.52j" )
|F | = 0.2298 N
Therefore, the magnitude of the magnetic force on the wire is 0.2298 N
Answer:A.
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