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ollegr [7]
3 years ago
9

In an unusually detailed dissection of your dinner, you isolate an unknown fatty acid. it is a liquid at room temperature (that

is, has a low melting point and contains carbon-carbon double bonds. what are you most likely to be eating?
Physics
1 answer:
3241004551 [841]3 years ago
6 0
Based on the description that given above, i think you're most likely eating: a plant
Fatty acids that contain carbon-carbon double bonds and liquid in a room temperature are most likely to be unsaturated fats.
The food source that contains a high amount of unsaturated fats tends to be plant based.
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PolarNik [594]

Answer: The plasma membrane is called a selectively permeable membrane as it permits the movement of only certain molecules in and out of the cells. Not all molecules are free to diffuse. If plasma membrane ruptures or breaks down then molecules of some substances will freely move in and out of the cells.

7 0
3 years ago
Can an object be accelerated while traveling at constant velocity? Why or why not?
AysviL [449]

Answer:

An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes. If an object's velocity is constant, however, its acceleration will be zero.

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3 years ago
A girl of mass 55 kg throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of 25 m/s
lisabon 2012 [21]

Answer:

Magnitude of the average force exerted on the wall by the ball is 800N

Explanation:

Given

Contact Time = t = 0.05 seconds

Mass (of ball) = 0.80kg

Initial Velocity = u = 25m/s

Final Velocity = 25m/s

Magnitude of the average force exerted on the wall by the ball is given by;

F = ma

Where m = 0.8kg

a = Average Acceleration

a = (u + v)/t

a = (25 + 25)/0.05

a = 50/0.05

a = 1000m/s²

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3 0
3 years ago
Explain the principles of effective team
steposvetlana [31]

Answer:

work relationship built on trust.

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5 0
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A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When re
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Answer:

(1) V = 0.2 J (2) 0.05J

Explanation:

Solution

Given that:

K = 160 N/m

x = 0.05 m

Now,

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Thus,

V = 1/2 kx² = 0.5 * 160 * (0.05)²

Therefore V = 0.2 J

(2)Now, we solve for how much of the internal energy is produced as the toy springs up to its maximum height.

By using the energy conversion, we have the following

ΔV = mgh

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The internal energy = 0.2 -0.15

=0.05J

8 0
3 years ago
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