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ollegr [7]
3 years ago
9

In an unusually detailed dissection of your dinner, you isolate an unknown fatty acid. it is a liquid at room temperature (that

is, has a low melting point and contains carbon-carbon double bonds. what are you most likely to be eating?
Physics
1 answer:
3241004551 [841]3 years ago
6 0
Based on the description that given above, i think you're most likely eating: a plant
Fatty acids that contain carbon-carbon double bonds and liquid in a room temperature are most likely to be unsaturated fats.
The food source that contains a high amount of unsaturated fats tends to be plant based.
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Our lives would big be possible because we would not be able to drive cars all knots would untie
5 0
3 years ago
A friend claims that her car can accelerate from a stop to 60 mi/h (26.8 m/s) in 5.1 s , but the speedometer is broken. You deci
Lemur [1.5K]

I attached a diagram, according to the description given, to better understand the problem. The car accelerates, at a 'a' speed, which will also experience the hanging object, in two components:

The one in x, with 'a' in the opposite direction to the car's address

The one found in y, the product of gravity. The two components are related through the tangent and the respective angle, as well,

tan\theta = \frac{ma}{mg}

tan\theta = \frac{a}{g}

To identify, we know that it can be expressed as a function of speed,

a= \frac{\Delta v}{t} = \frac{v-u_0}{5.1}\frac{26.8}{5.1}

a=5.26m/s^2

Replacing in our angle formula,

tan\theta = \frac{5.26}{9.8}

tan\theta = 0.54

\theta = tan^{-1}(0.54)

\theta = 28.4\°

If there is no friction, we consider the vertical forces of both the Washes and the Normal car. So,

F=ma

Therefore the relationship with the vertical component would be given by,

\Rightarrow \frac{F}{mg} = \frac{ma}{mg} = \frac{a}{g}=\frac{5.26}{9.8}=0.54 =54\%

4 0
3 years ago
A 250 g air-track glider is attached to a spring with springconstant 4.0 N/m. Th damping constant due to air resistance is0.015
vaieri [72.5K]

Answer:

33.33 seconds

Explanation:

N=\dfrac{1}{e}N_0

N_0 = Initial length pulled = 20 cm

b = Damping constant = 0.015 kg/s

k = Spring constant = 4 N/m

m = Mass of glider = 250 g

Time period is given by

T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{0.25}{4}}\\\Rightarrow T=1.57079632679\ s

Using exponential decay formula

N=N_0e^{\dfrac{-bt}{m}}

Final amplitude = Initial times decay

\dfrac{1}{e}0.2=0.2e^{\dfrac{-0.015t}{2\times 0.25}}\\\Rightarrow 0.2=0.2e^{\frac{-0.015t}{2\cdot \:0.25}+1}\\\Rightarrow e^{\frac{-0.015t}{2\cdot \:0.25}+1}=1\\\Rightarrow \ln \left(e^{\frac{-0.015t}{2\cdot \:0.25}+1}\right)=\ln \left(1\right)\\\Rightarrow \left(\frac{-0.015t}{2\cdot \:0.25}+1\right)\ln \left(e\right)=\ln \left(1\right)\\\Rightarrow \frac{-0.015t}{2\cdot \:0.25}+1=\ln \left(1\right)\\\Rightarrow -\frac{0.015t}{0.5}=-1\\\Rightarrow -0.000225t=-0.0075\\\Rightarrow t=33.33\ s

The time taken is 33.33 seconds

7 0
3 years ago
Suzie stands on a pedestal and touches the dome of a running Van de Graaf generator. In a few seconds she observes her hair stan
arlik [135]

Answer:A

Explanation:

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The tidal bulge on the side of the earth opposite the moon is due to _______ .
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Due to the moon's gravitational force and inertias counterbalance.
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