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ollegr [7]
3 years ago
9

In an unusually detailed dissection of your dinner, you isolate an unknown fatty acid. it is a liquid at room temperature (that

is, has a low melting point and contains carbon-carbon double bonds. what are you most likely to be eating?
Physics
1 answer:
3241004551 [841]3 years ago
6 0
Based on the description that given above, i think you're most likely eating: a plant
Fatty acids that contain carbon-carbon double bonds and liquid in a room temperature are most likely to be unsaturated fats.
The food source that contains a high amount of unsaturated fats tends to be plant based.
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(a) The spring constant is 500 N/m.

(b) The extension of the spring when 25 N force is applied is 0.05 m.

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The given parameters:

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The spring constant is calculated as follows;

F = kx\\\\k = \frac{F}{x} \\\\k = \frac{10}{20 \times 10^{-3}} \\\\k = 500 \ N/m

The extension of the spring when 25 N force is applied is calculated as follows;

F = kx\\\\x = \frac{F}{k} \\\\x = \frac{25}{500} \\\\x = 0.05 \ m

The applied force to cause an extension of 5 mm is calculated as follows;

F = kx\\\\F = 500 \times 5 \times 10^{-3}\\\\F = 2.5 \ N

Learn more about Hook's law here: brainly.com/question/12253978

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In an oscillating lc circuit, when 75.0% of the total energy is stored in the inductor's magnetic field, (a) what multiple of th
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3 years ago
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dybincka [34]

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3 0
4 years ago
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Now  sin (Theta) = opposite side/hypotenuse

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4 years ago
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