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elixir [45]
3 years ago
8

How is a refracting telescope similar to a compound microscope?

Physics
2 answers:
Flura [38]3 years ago
5 0

They both have an objective lens and an eyepiece lens.

s2008m [1.1K]3 years ago
4 0

Answer:

There are two similarities between refracting telescope and compound microscope.

1. both have objective lens and eyepiece lens

2. both the lenses are convex in nature.

Explanation:

Objective lens is near the object and eyepiece is near the eye through which we can see the image.

Convex or converging lens is used to converge the rays of light coming from the object.

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A positively charged glass rod is bought close to a suspended metal needle. What
Darina [25.2K]

Answer:

attracted

Explanation:

opposite charges attract each other when the rub against each other

7 0
3 years ago
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Compared with the amount of current in the filament of a lamp, the amount of current in the connecting wire is A. definitely les
pashok25 [27]

Compared with the amount of current in the filament of a lamp, the amount of current in the connecting wire is

D. the same.

As per the rule, the amount of current in devices connected in series is equal. here in the given situation , the wire is in series with the filament. that is the reason that the current in filament and wire is same.

hence the correct choice is D)

8 0
3 years ago
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Most chemical reactions can be divided into how many main groups?
tatyana61 [14]
There is synthesis
decomposition
double displacement
single displacement
combustion
metathesis
so i guess you could say 6
5 0
3 years ago
Why is friction like applied force but different from gravity?
kirill115 [55]

Answer:

Friction is when a force is applied or done by weight dragging onto something.

Explanation:

Gravity is when an object is getting pulled toward the center of what is attracting it. And applied force is when someone/sommething is applying force.

3 0
3 years ago
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A thin walled spherical shell is rolling on a surface. What
ExtremeBDS [4]

Answer:

=\frac{1/3}{5/6} = 0.4

Explanation:

Moment of inertia of given shell= \frac{2}{3} MR^2

where

M represent sphere mass

R -sphere radius

we know linear speed is given as v = r\omega

translational K.E = \frac{1}{2} mv^2 = \frac{1}{2} m(r\omega)^2

rotational K.E = \frac{1}{2} I \omega^2 = \frac{1}{2} \frac{2}{3} MR^2 \omega^2

total kinetic energy will be

K.E = \frac{1}{2} m(r\omega)^2 + \frac{1}{2} \frac{2}{3} MR^2 \omega^2

K.E =\frac{5}{6} MR^2 \omega^2

fraction of rotaional to total K.E

=\frac{1/3}{5/6} = 0.4

8 0
3 years ago
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