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Alona [7]
3 years ago
10

Which of the following correctly describes the domain of the function shown

Mathematics
1 answer:
labwork [276]3 years ago
4 0

Option D:

\{x: x \neq 1\} is the domain of the function.

Solution:

Given function is

$r(x)=\frac{2 x}{x-1}

<u>To find the domain of the function:</u>

Option A: \{x: x \neq 0\}

Substitute x = 0 in r(x).

$r(0)=\frac{2 \times 0}{0-1}=0

If x = 0, then r(0) = 0

So that x ≠ 0 is false.

So, \{x: x \neq 0\} is not the domain of the function.

Option B: \{x: x \neq \pm 1\}

Substitute x = –1 in r(x).

$r(-1)=\frac{2 \times (-1)}{-1-1}=1

If x = –1, then r(–1) = 1

So that x = ± 1 is false.

So, \{x: x \neq \pm 1\} is not the domain of the function.

Option C: $\{x: \text { all real numbers }\}$

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, all real numbers are not the domain of the function.

Option D: \{x: x \neq 1\}

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, \{x: x \neq 1\} is the domain of the function.

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We will start by getting the slope of CD using the formula:
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We know that the line we are looking for is perpendicular to CD. This meas that the product of their slopes is -1. Knowing this, and having calculated the slope of CD, we can simply get the slope of our line

2- getting the y-intercept:
To get the y-intercept, we will need a point that belongs to the line.
We know that our line passes through the midpoint of CD.
Therefore, we will first need to get the midpoint:
midpoint = (\frac{x1+x2}{2} ,  \frac{y1+y2}{2})

Now, we will use this point along with the slope we have to substitute in the general equation and solve for c.

By this, we would have our equation in the form of:
y = mx + c

Hope this helps :)


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You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio
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Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

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Answer:

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Hence, the function rule can be written has :

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