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3 years ago

5

A bag contains 1 gold marbles, 6 silver marbles, and 30 black marbles. Someone offers to play this game: You randomly select on

marble from the bag. If it is gold, you win $4. If it is silver, you win $2. If it is black, you lose $1. You can expect to lose an average of ________ cents every time you play. (round to the nearest cent)

1 answer:

Feliz [49]3 years ago

7 0

You have a 30 out of 37% chance so i would say 53 cents
i hope this helps at least a little

good luck!

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the table below shows the function of f determine the value of f(3) that will lead to an average rate of change of 19 over the i

3241004551 [841]

ANSWER

$f(3) = - 25$

EXPLANATION

We want to determine the value of f(3) that will lead to an average rate of change of 19 over the interval [3, 5].

The average rate of change of f(x) over the interval [a,b]:

$= \frac{f(b) - f(a)}{b - a}$

If the average rate of change over the interval [3, 5] is 19, then;

$\frac{f(5) - f(3)}{5 - 3} = 19$

From the to table f(5)=13

$\frac{13 - f(3)}{2} = 19$

$13 - f(3) = 19 \times 2$

$13 - f(3) = 38$

$- f(3) = 38 - 13$

$- f(3) = 25$

$f(3) = - 25$

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2 years ago

What is the sum of 1 - 0.5 + 899

I am Lyosha [343]

Answer:

899.5

Step-by-step explanation:

8 0

3 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

2 years ago

PLZ help really super fast

BaLLatris [955]

Answer:

B

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

F (×)=-4×^2-3 g (×)-3×-3 Find f (4)and g(5)

Elena-2011 [213]

F(4)= -64-3=-69 g(5)= -15-3=-18

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2 years ago