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3 years ago

How do I transform the equations 5x+4y=8 and -2x+5y=30 so that they are in the form that y=MX+b?

2 answers:

6 0

4y=5x+8 5y=-2x+30 the y always goes first. then the equal sign. next is x and finally just the digit which is also known as "b".

Feliz [49]3 years ago

6 0

Make y the subject for both equations:

5x + 4y = 8
4y = -5x + 8
y = -(4/5)x + 8

-2x + 5y = 30
5y = 2x + 30
y = (2/5)x + 6

There you go, both equations are in y = mx + b for :)

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Please solve this question.

egoroff_w [7]

<h3><u>Answer</u> :</h3>

Let numerator of fraction be x and denominator be y.

∴ Fraction = x/y

★ <u>Part - A</u> :

$:\implies\tt\:\dfrac{x\times 4}{y-2}=2$

$:\implies\tt\:4x=2(y-2)$

$:\implies\tt\:4x=2y-4$

$:\implies\tt\:2y=4x+4$

$:\implies\bf\:y=2x+2\:\:\dots (1)$

★ <u>Part</u><u> </u><u>-</u><u> </u><u>B</u> :

$:\implies\tt\:\dfrac{x+15}{2y-2}=\dfrac{9}{7}$

$:\implies\tt\:7(x+15)=9(2y-2)$

$:\implies\tt\:7x+105=18y-18$

From equation (1)...

$:\implies\tt\:7x+105=18(2x+2)-18$

$:\implies\tt\:7x+105=36x+38-18$

$:\implies\tt\:29x=105-18$

$:\implies\tt\:x=\dfrac{87}{29}$

$:\implies\boxed{\bf{x=3}}$

$:\implies\tt\:y=2x+2$

$:\implies\tt\:y=2(3)+2$

$:\implies\boxed{\bf{y=8}}$

∴ Fraction = x/y = 3/8

<h3>Hope It Helps!</h3>

5 0

3 years ago

Read 2 more answers

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