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Dmitry [639]
3 years ago
7

Patrick, Paulo, and Joseph divided 68 oranges. Patrick got two oranges less than Paulo and Paulo got twice as much as Joseph. Ho

w many oranges did Joseph get?
Mathematics
1 answer:
Tatiana [17]3 years ago
3 0
Let's say patrick=a, paulo=b and joseph=c:

(1) a+b+c=68
(2) a+2=b
(3) b=2c

substituting (2) in (1) gives:

(4) 2a + c = 66 => a = 33 - c/2

(3) in (2) gives:

(5) a+2=2c

(4) in (5):

33 - c/2 + 2 = 2c => 35 = 2.5c => c=14

Joseph got 14 oranges!


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The answer is:      "  3(m − 2)  "  .

__________________________________

  →  The "factorized version" of the binomial expression, " 3m − 6 " ,  is:

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                →   "  3(m − 2) " .

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Explanation:

To solve:

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<u>Note</u>:  We are given the expression:  " 3m − 6 " ;

and we are asked to "factorize" this expression.

Note that this expression is a "binomial expression" — which means there are two (2) terms — in this case:   "3m" and "6" .

Since only one (1) of these 2 (two) terms has a variable, and the remaining terms is a "constant" (non-zero integer), write these 2 (two) terms as:

 1)  the coefficient of the variable given in the term shown with a "coefficient" :

       →   that is:  "3"  ;  and:

 2)  the other term:  "6" .

→  With the numbers:  "3 and 6" , we can factor out a "3" ;  

          →  {since:  " 6 ÷ 3 = 2 "} ;

 →   So;  given:  

               " 3m − 6 " ;  

 →   We can "factor out" a "3" ; as follows:

           →   Take the first term:  " 3m " :

                    " 3m  =  3 * m " ;

__________________________________

           →   Take the second term:  "  6 " :

                    "  6 = 3 * (what value?) ;

                 → divide each of this equation by "3" ;

    to isolate the "missing value" on one side of the equation; & to solve for the "missing value" ; as follows:

        →           "  6 / 3 = [ 3 * (what value?) ] / 3  ;

                    →  to get:  " 2  =  "(the missing value)"  ;

    →   So;    "  6 = 3 * (what value?) ;

           →     " 6 = 3 * 2 " .  

           →   Take the second term:  "  6 " :

           →     " 6 = 3 * 2 " .

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So:    " 3m − 6 "  =  (3 * m) − (3 * 2) " .  

Factor out a "3" ;  as follows:

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    →  " 3m − 6 "  =  (3 * m) − (3 * 2) " ;

                           =   " 3(m − 2)  "

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Let us check our answer:

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Note the "distributive property of multiplication"  :

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        a(b + c) = ab +  ac ;  

        a(b − c) = ab −  ac ;

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So:  Take our answer:  " 3(m − 2) " .

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" 3(m − 2)  = ?  (3*m)  −  (3*2)  " ??  ;

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Let us substitute "4" for "m" ;  in both sides of the equation;

              →  to see if the equation holds true;  i.e. to see if both sides of the equation are equal when:  " m = 4 " ;

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 We have:

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     →  " 3(m − 2)  = ?  (3*m)  −  (3*2)  " ??  ;

First let us rewrite this equation;  substitute "4" for "m" ; as follows:

     →   " 3(4 − 2)  = ?  (3*4)  −  (3*2)  " ??  ;

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And calculate;  to see if each side of the equation is equal ; i.e. to see if the equation holds true; as follows:

     →   " 3(2)  = ?  (12)  −  (6)  " ??  ;

     →   "  6  = ?  (6)  " ??  ;

     →   "  6 = 6 " !  Yes!  The equation holds true!

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Hope this answer was helpful!

Best wishes!

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