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MAVERICK [17]
3 years ago
11

Can someone answer all 3 thanks.

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

All of them are yes because you either subtract or add to put in the form of mx+b

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If x+1/x = 5 find the value of x^3 +1/x^3. pls solve​
Korolek [52]

Answer:

1) solve x+1/x = 5

\frac{x + 1}{x}  = 5

x + 1 = 5x

x - 5x =  - 1

- 4x =  - 1

x =  \frac{ -1}{ - 4}

x =  \frac{1}{4}

2) solve x³+1/x³

x {}^{3}  +  \frac{1}{x {}^{3} }

substitute x = 1/4 into the expression

( \frac{1}{4} ) {}^{3}  +  \frac{1}{( \frac{1}{4}) {}^{3}  }

\frac{1}{64}  +  \frac{1}{ \frac{1}{64} }

\frac{1}{64}  +  \frac{64 \times 1}{1}

\frac{1}{64}   + 64

\frac{4097}{64}  \: or \: 64.02

5 0
3 years ago
All the given quadrilaterals in the picture on the right are squares and #1 ≅ #3, #2 ≅ # 4. find the area of the shaded region,
Anika [276]

Answer:

Step-by-step explanation:

If you have a square of side l, its diagonal would be l\sqrt{2}, and its area l^2

If the big square has a area of 900, this implies that its side is \sqrt{900}, so the two diagonal of squares 2 and 4 added together would be \sqrt{900}, therefore one diagonal wold be \frac{\sqrt{900}}{2}. and its side \frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}}. The area (of one square) is (\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}})^2=\frac{225}{2}

finally the two areas combined (squares 2 and 4) would be 225

6 0
2 years ago
Someone please help with this
Citrus2011 [14]

Answer:

g(-3) = 1

Step-by-step explanation:

We use the top piece of the function since x = -3

g(-3) = x+4 and x = -3

g(-3) = -3 +4 = 1

3 0
3 years ago
Can someone help me out on these 2 geometry questions pls? ASAP!!!
Katena32 [7]

<u>Question 2</u>

1) \overline{PR} \perp\overline{QS}, \overline{PQ} \cong \overline{PS} (given)

2) \overline{PR} \cong \overline{PR} (reflexive property)

3) \angle PRQ, \angle PRS are right angles (perpendicular lines form right angles)

4) \triangle PRQ, \triangle PRS are right triangles (a triangle with a right angle is a right triangle)

5) \triangle PRQ \cong \triangle PRS (HL)

<u>Question 3</u>

1) \angle C is a right angle, \overline{AC} \cong \overline{AE}, \overline{DE} \perp \overline{AB} (given)

2) \angle DEA is a right angle (perpendicular lines form right angles)

3) \triangle ACD, \triangle DAE are right triangles (a triangle with a right triangle is a right angle)

4) \overline{AD} \cong \overline{AD} (reflexive property)

5) \triangle ACD \cong \triangle AED (HL)

6) \angle CAD \cong \angle DAE (CPCTC)

7) \overline{AD} bisects \angle BAC (if a segment splits an angle into two congruent parts, it is an angle bisector)

6 0
2 years ago
5,820 in scientific notation
Ivan

Answer:

Step-by-step explanation:

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 5,820

New Number: 5.820

Step 2

Now, to find b, count how many places to the right of the decimal.

New Number: 5 . 8 2 0

Decimal Count:   1 2 3

There are 3 places to the right of the decimal place.

Step 3

Building upon what we know above, we can now reconstruct the number into scientific notation.

Remember, the notation is: a x 10b

a = 5.82 (Please notice any zeroes on the end have been removed)

b = 3

Now the whole thing:

5.82 x 103

Step 4

Check your work:

103 = 1,000 x 5.82 = 5,820

4 0
3 years ago
Read 2 more answers
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