A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit
"The sum of the digits is 5"
x + y = 5
The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]
The number is: 10x + y
3(10x + y) = 42
The system of equations: (two equations for two unknowns)
x + y = 5
30x + 3y = 42
Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out
-3x - 3y = -15
30x + 3y = 42
------------------
27x + 0 = 27
x = 1
then plug x = 1 into either equation to find y
1 + y = 5
y = 4
remember the x and y represent digits so the number xy is 14
Is there more to this problem? By saying f(4), you'd be inputting a 4 for every variable x. There is not enough info here to answer the question.
Answer:
answer is 3
there are two ways to solve it. I hope you understand.
Answer:
-9n^6
Step-by-step explanation:
(−9n^3)(n^3)
=(−9) * n^3 * n^3
=−9 * n^6
=−9n^6
i’ll try to help.
angle 3 and angle 1 are congruent angles, so they both equal 75°.
angle 1 and angle 5 are corresponding angles, so they both equal 75°. (it’s bc they’re positioned the same.
soooo the answer to that is 75° for angle 5. (not really great at explaining) also hope that the answer is right it should be.
