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Dafna1 [17]
2 years ago
9

Do exponential functions have horizontal asymptotes?

Mathematics
1 answer:
vladimir1956 [14]2 years ago
4 0

9514 1404 393

Answer:

  yes

Step-by-step explanation:

The parent function e^x has a horizontal asymptote at y=0.

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A 3ed degree binomial with a constant term of 8
Svet_ta [14]

Answer:

4m³+8 is a 3rd degree binomial with constant term of 8.

Step-by-step explanation:

  • A binomial expression consists of two terms.

For example,

m+n is a binomial, where m and n are two terms.

  • As we know that the degree of the polynomial is said to be the highest exponent of any of the terms.

For example, in expression 7m + 3, the exponent of m is 1. So it is 1st degree polynomial.

Similarly, in the expression 10m²+9m, variable m has the highest exponent which is 2. So it is 2nd degree polynomial.

Now, let us write a 3rd degree binomial with a constant term of 8

4m³+8

As it has two terms which are 4m³ and 8, Therefore, it would be called binomial.

Also the highest exponent with variable m is 3. Therefore it would be a 3rd degree binomial with constant term of 8.

7 0
3 years ago
Round 56.834 to the nearest tenth
k0ka [10]

Answer:

56.8

Step-by-step explanation:

8 is the tenth

numbers that are 4 or under stay the same

numbers that are 5 or above round up

8 0
3 years ago
Read 2 more answers
Can anyone explain please?
frosja888 [35]

Answer:

x = 55

Step-by-step explanation:

In a rhombus, each diagonal bisects a pair of opposite angles.

For this parallelogram t be a rhombus, the angles with measures 2x - 40 and x + 15 must be congruent.

2x - 40 = x + 15

Subtract x from both sides.

x - 40 = 15

Add 40 to both sides.

x = 55

4 0
2 years ago
Read 2 more answers
Find how many two digit numbers are divisible by 3
Bad White [126]

I'll use arithmetic series to find it.

First two-digit number divisible by 3 is 12, last such number is 99. Every 3rd number is divisible by 3.

So,

a_1=12\\a_n=99\\d=3\\n=?\\\\a_n=a_1+(n-1)\cdot d\\99=12+(n-1)\cdot 3\\3n-3=87\\3n=90\\n=30

<u>There are 30 such numbers.</u>

7 0
3 years ago
Question 1:
Morgarella [4.7K]

Answer:

Step-by-step explanation:

KE = ½mv²

KE₁₀ = ½(1100)10² = 55000 = 55 kJ

KE₃₀ = ½(1100)30² = 495000 = 495 kJ

9 times greater

3 0
2 years ago
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