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Mnenie [13.5K]
3 years ago
6

after taking math online . what would you say are some pross (good) and cons (bad) about taking classes . online? what would mak

e it better?​
Mathematics
2 answers:
DerKrebs [107]3 years ago
6 0

After taking online classes, there are some pros and cons. The positive side of taking online classes are that you learn at a much faster rate, you have more choices and flexibilty with your education, and you're able to do it wherever you want with the comfort of your home. The negative side of taking online classes are that it's very expensive to take online classes, there's a higher chance of the student cheating instead of learning the lesson, and the lack of self-motivation, the increase in work can be stressful!

(This is in my own words, so I hope this helps!)

Elden [556K]3 years ago
5 0

Answer:

Cons: Could be harder, Difficult to solve, hard to see problems online, Things to help: Post assignments in portions Pros: hand wont hurt if writing, Wont loose paper if it’s on paper

Step-by-step explanation:

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Tank 1 initially contains 50 gals of water with 10 oz of salt in it, while tank 2 initially contains 20 gals of water with 15 oz
Naddik [55]
\dfrac{\mathrm dx_1}{\mathrm dt}=\dfrac{2\text{ oz}}{1\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}-\dfrac{x_1(t)\text{ oz}}{50\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}
\dfrac{\mathrm dx_2}{\mathrm dt}=\dfrac{x_1(t)\text{ oz}}{50\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}-\dfrac{x_2(t)\text{ oz}}{20\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}

\implies\begin{cases}\dfrac{\mathrm dx_1}{\mathrm dt}=10-\dfrac1{10}x_1\\\\\dfrac{\mathrm dx_2}{\mathrm dt}=\dfrac1{10}x_1-\dfrac14x_2\\\\x_1(0)=10\\\\x_2(0)=15\end{cases}
6 0
3 years ago
Which points are on the graph of g(x) = (1/5)^x
11111nata11111 [884]

Answer:

A) The point( -1 , 5)  is satisfies the  given graph  g(x) = (\frac{1}{5} )^{x}

B) The point( 3 , 1/125)  is satisfies the  given graph  g(x) = (\frac{1}{5} )^{x}

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given graph  

               y =      g(x) = (\frac{1}{5} )^{x}

Put the point ( -1 , 5)

Put y =5 and x =-1

            5 = (\frac{1}{5} )^{-1} = 5

The point( -1 , 5)  is satisfies the  given graph

ii)

Given graph  

               y =      g(x) = (\frac{1}{5} )^{x}

             \frac{1}{125}  = (\frac{1}{5} )^{3} = \frac{1}{125}

The point( 3 , 1/125)  is satisfies the  given graph  g(x) = (\frac{1}{5} )^{x}

                 

7 0
3 years ago
Do anyone think this is right ?
mestny [16]
It is not true because there C and E are on different sides, if that makes sense (which means your answer is correct)
6 0
3 years ago
Read 2 more answers
Adding negative numbers
jekas [21]

Step-by-step explanation:

-5 × -5 = 25

-6 + 5 = 1

-3 + 5 = -8

6 0
2 years ago
Given the data shown below, which of the following is the best approximation of the coefficient of determination (r^2)
HACTEHA [7]

The coefficient of determination can be found using the following formula:

r^2=\mleft(\frac{n(\sum ^{}_{}xy)-(\sum ^{}_{}x)(\sum ^{}_{}y)}{\sqrt[]{(n\sum ^{}_{}x^2-(\sum ^{}_{}x)^2)(n\sum ^{}_{}y^2-(\sum ^{}_{}y)^2}^{}}\mright)^2

Using a Statistics calculator or an online tool to work with the data we were given, we get

So the best aproximation of r² is 0.861

8 0
1 year ago
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