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Oduvanchick [21]
4 years ago
8

Find dimensions of the rectangular box of maximum volume that can be inscribed in a sphere of radius a?

Mathematics
1 answer:
ivolga24 [154]4 years ago
4 0
This is an optimization calculus problem where you would need to know a little bit more about the box, atleast i would think. You would just need to use the volume equation of a sphere as the restrictive equation in the optimization problem. Perhaps there is a way to solve with the given information, but i do not know how to.
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Melissa read 4 books each week for 4 weeks. Amanda read 5 books a week for 4 weeks. How many more did Amanda read? Choose the an
wariber [46]

Answer:

Amanda read 4 for than Melissa.

Step-by-step explanation:

Amanda read 20 and Melissa read 16. 20-16=4.

6 0
3 years ago
Each month, Anna pays $630 in rent. How much rent does she pay over the course of 18 months?
Ilia_Sergeevich [38]

Answer:

$11,340

Step-by-step explanation:

1 month: 630

18 months: 18×630=11,340

7 0
4 years ago
Simplify: 2cd3 (c- d+5)
sasho [114]

Answer:

2c2d3 − 2cd4 + 10cd3

hope it helps

6 0
3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
What conclusion can be derived by comparing the central tendencies of the two data sets?
valentinak56 [21]
B i hope this helps you
4 0
3 years ago
Read 2 more answers
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