Answer:
A. E(x) = 1/n×n(n+1)/2
B. E(x²) = 1/n
Step-by-step explanation:
The n candidates for a job have been ranked 1,2,3....n. Let x be the rank of a randomly selected candidate. Therefore, the PMF of X is given as
P(x) = {1/n, x = 1,2...n}
Therefore,
Expectation of X
E(x) = summation {xP(×)}
= summation {X×1/n}
= 1/n summation{x}
= 1/n×n(n+1)/2
= n+1/2
Thus, E(x) = 1/n×n(n+1)/2
Value of E(x²)
E(x²) = summation {x²P(×)}
= summation{x²×1/n}
= 1/n
Data:
<span>Number of shares: 500
name of fund
nav offer price
hat mid-cap $18.94 $19.14
Profit $6,250.
1) Investment = number of shares * offer price = <em />500 * $ 19.14 = $ 9570
2) Total net value = profit + investment = $6250 + $9570 = $15820
3) NAV = total net value / number of shares = $15820 / 500 = $31.64
Answer: option c: 31.64
</span>
T= sqrt(5/wc)
remove ( )
T= 5sqrt/wc
multiply by wc
Twc=5sqrt
divide by Tc
W= 5sqrt/cT
hope this helps
Its the y=3x2one pretty sure
point slope form of a line
y-y1 = m(x-x1)
y-7 = -2 (x-1)
if you want it in slope intercept form
y-7 = -2x +2
add 7 to each side
y = -2x +9
