Let us assume that it is 1/8 lb packages of fudge.
So, the question is how many 1/8 lbs of fudge can be sold from 7 pounds of fudge
Answer:
Total amount of fudge = 7 pounds
Portions of division = 1/8 pounds
So, number of packages that can be made from 7 pounds are =
= 
Hence, 56 packages of 1/8 lbs each can be made from 7 pounds fudge.
Answer:
I DONT KNOW IM VERY SORRY CAN JUST PLEASE GIVE ME 5 STARS I WOULD APPRECIATE IT VERY MUCH...
Step-by-step explanation:
Step-by-step explanation:
You would solve it by turning it into a equation and solving it. You would place the dots on the graph and put them in the points where they are supposed to go.
Answer: 10, 11, & 12
<u>Step-by-step explanation:</u>
Let x represent the age of the youngest child.
Their ages are consecutive so,
Youngest: x
Middle: x + 1
Oldest: x + 2
The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.
x² = 8(x + 2) + 4
x² = 8x + 16 + 4
x² = 8x + 20
x² - 8x - 20 = 0
(x - 10)(x + 2) = 0
x - 10 = 0 or x + 2 = 0
x = 10 or x = -2
Since age cannot be negative, x = -2 is not valid
So, the Youngest (x) is 10
the Middle (x + 1) is 11
and the Oldest (x + 2) is 12
Answer:
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8)</span></span></span></span>
Explanation:
write as : <span>y=50000<span><span>(0.8)</span>x</span></span>
Taking logs:
<span><span>log<span>(y)</span></span>=<span>log<span>(50000)</span></span>+<span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span></span>
But <span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span> is the same as <span>x<span>log<span>(0.8)</span></span></span>
Thus
<span>x=<span><span><span>log<span>(y)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
</span></span></span></span></span>Now swap the x'x and the y's giving:<span><span><span><span><span>
</span></span></span></span></span>
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
my teacher helped a little bit
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