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jeka94
3 years ago
12

Which of the following goes through (-2,4)

Mathematics
1 answer:
Setler79 [48]3 years ago
8 0
-3x+y=10 is the answer. If you plug the coordinates in to the respective spots (-2 for x and 4 for y), you will get an equal true statement.
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PART1
Mice21 [21]
Part 1:\frac{5x^{3} + 10x^{2} + 15x}{5x} = \frac{5x^{3}}{5x} + \frac{10x^{2}}{5x} + \frac{15x}{5x} = x^{2} + 2x + 3
The answer is C.

Part 2:\frac{3x^{4} + 5x^{2} + 2x}{x} = \frac{3x^{4}}{x} + \frac{5x^{2}}{x} + \frac{2x}{x} = 3x^{3} + 5x + 2
The answer is A.
8 0
4 years ago
Which equation has the same solutions as 2x^2+16x-10=0 a) (x+4)^2=-3 b) (x+4)^2=-11 c) (x+4)^2=13 d) (x+4)^2=21
ikadub [295]
I'm working on the same thing down load the algebra tiger it really helps a lot I promise I use it daily to help with these
4 0
3 years ago
List three values that would make this inequality true 180 > 15y
vodka [1.7K]
As long as the number plugged in Times 15 is less than 180, it works
Here are your three values: 1,2,3
8 0
3 years ago
Read 2 more answers
4. If y = 5x – 3 and 3x - y = -1, what is the value of y? <br>A 2<br>B -1 <br>C 7 <br>D -8​
notsponge [240]

answers:

4.C po

Step-by-step explanation:

i hope its help

6 0
3 years ago
25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]
masha68 [24]
25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]  \\ 25-[2+5y-3y-6]=-6y+15-[5y-5-3y+3] \\ 25-2-5y+3y+6=-6y+15-5y+5+3y-3 \\ -2y+29=-8y+17 \\ 6y+29=17 \\ 6y=-12 \\ y=-2
Hope this helped :)
6 0
3 years ago
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