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3 years ago

Find the product of (2x + 3) and (x + 5)

Mathematics

1 answer:

forsale [732]3 years ago

6 0

Answer:

2x^2 + 13x + 15

Step-by-step explanation:

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Look at pic 10 pts will mark brainilest

seropon [69]

Answer:

c may be the correct one l am 55% sure

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2 years ago

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From the given sides of 16, 14, and 21, determine what type of triangle it will form (right, acute, obtuse, none).

Komok [63]

Answer:

It is an acute triangle.

Step-by-step explanation:

It would be much easier for you to see where I'm getting at if you draw a diagram.

Assume this triangle is labelled ABC where a = 14, b = 21, and c = 16.

cos A = (16^2 + 21^2 - 14^2)/(2(16)(21))

∠A = cos^-1(0.82291...)

∠A ≅ 34.6°

cos B = 16^2 + 14^2 - 21^2)/(2(16)(14))

∠B = cos^-1(0.024...)

∠B ≅ 56.8°

∠C = 180 - (∠A + ∠B)

∠C ≅ 56.8°

Since there is no right-angle nor is there an obtuse angle,

Therefore the triangle is an acute triangle.

4 0

3 years ago

A line passes through the point (6, -1) and has a slope of 3/2 Write an equation in slope-intercept form

Luda [366]

9514 1404 393

Answer:

y = 3/2x -10

Step-by-step explanation:

The point-slope equation can be written ...

y = m(x -h) +k . . . . . for a line with slope m through point (h, k)

Using the given values, this is ...

y = (3/2)(x -6) -1 = 3/2x -9 -1

y = 3/2x -10 . . . . . slope-intercept equation

6 0

3 years ago

Need answer ASAP pls

jarptica [38.1K]

Answer:

$Distance(PQ)=\sqrt{113}$

Step-by-step explanation:

In coordinate geometry distance between the two points can be find by using the distance formula:

For two points :

$(x_1,y_1)\\and \\(x_2,y_2)$

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For points: P(3,-1) and Q(-5,6)

Distance (PQ):

$=\sqrt{(-5-3)^2+(6-(-1))^2} \\\\=\sqrt{(-8)^2+(6+1)^2}\\\\ =\sqrt{(-8)^2+(7)^2} \\\\=\sqrt{64+49}\\\\Distance(PQ) =\sqrt{113}\\\\$

5 0

2 years ago

Can somebody help me with this please

UNO [17]

I think the answer to 1 is Friday

8 0

3 years ago

Read 2 more answers