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Olegator [25]
3 years ago
10

Find the product of (2x + 3) and (x + 5)

Mathematics
1 answer:
forsale [732]3 years ago
6 0

Answer:

2x^2 + 13x + 15

Step-by-step explanation:

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Julie is a math tutor. She charges each student $210 for the first 7 hours of tutoring and $20 for each additional hour.
Maksim231197 [3]
She spent 17 hours tutoring

$210 = 7 hours

$20 x 10 hours = $200

$210 + $200 = $410
7 Hours + 10 Hours = 17 Hours

8 0
3 years ago
Read 2 more answers
Show work please :: I forgot how to solve
Vesna [10]
40 pages = 80 minutes
210 pages = ? minutes
Well, take the first fact; 40 pages in 80 minutes and use it to find how many pages per minute.
40/80=1/2
1/2 pages = 1 minute
1 page = 2 minutes
210 pages = ? minutes
210*2=420
420 minutes = 7 hours
210 pages = 7 hours
Hope this helped :)
4 0
3 years ago
H(n) = 3^n+3; Find h (3n)
olya-2409 [2.1K]

Answer:

The option which you chose is absolutely right.

Step-by-step explanation:

h(n) = 3^ n + 3

h(3n) = 3 ^3n + 3

Hope it will help :)

5 0
3 years ago
Area can be defined as the number of cubic units it takes to fill the inside of a
RoseWind [281]

Answer:

False

Step-by-step explanation:

Area is the number of square units it tales to fill the inside of a polygon.

7 0
3 years ago
Read 2 more answers
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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