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zheka24 [161]
3 years ago
10

PLease help on this one? <3

Mathematics
2 answers:
lutik1710 [3]3 years ago
6 0

D

hope this helps you

SOVA2 [1]3 years ago
5 0

Answer:

The correct option is D.

Step-by-step explanation:

From the given above it is clear that coordinate pairs of given function are

f = {(1,1.25), (2,2.50), (5,6.25), (15,18.75), (20,25.00)}

If a function is defined as

f(x)=\{(x,y):x\in R,y\in R \}

then the inverse of function is defined as

f(x)=\{(y,x):x\in R,y\in R \}

The coordinate pairs of inverse of given function are

f⁻¹ = {(1.25,1), (2.50,2), (6.25,5), (18.75,15), (25.00,20)}

These coordinate pairs represents by table in option D.

Therefore the correct option is D.

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I need help, please and thank you
borishaifa [10]

Answer:

See below ↓

Step-by-step explanation:

<u>Problem</u>

  • <u />\frac{5x}{x+7} + \frac{7}{x}

<u>Work</u>

  • <u />\frac{5x(x)+7(x+7)}{x(x+7)}
  • \frac{5x^{2} +7x+49}{x(x+7)}
  • The student's mistake was that instead of taking x(x + 7) as the LCM (Least Common Multiple), he took x + 7, which is not possible in this case

<u>Solution</u>

  • <u />\frac{5x^{2} +7x+49}{x(x+7)}
5 0
2 years ago
Let X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes. If the random vari
Gelneren [198K]

Answer:

Probability that the wait time is greater than 37 minutes is 0.3474.

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes.

<u><em>Let X = waiting time for a car to pass by on a country road</em></u>

The probability distribution function of exponential distribution is given by;

f(x) = \lambda e^{-\lambda x}  , x >0     where, \lambda = parameter of distribution.

Now, the mean of exponential distribution is = \frac{1}{\lambda}  which is given to us as 35 minutes that means  \lambda = \frac{1}{35}  .

So, X ~ Exp( \lambda = \frac{1}{35} )

Also, we know that Cumulative distribution function (CDF) of Exponential distribution is given as;

F(x) = P(X \leq x) = 1 - e^{-\lambda x}  , x > 0

Now, Probability that the wait time is greater than 37 minutes is given by = P(X > 37 min) = 1 - P(X \leq 37 min)

  P(X \leq 37 min) = 1 - e^{-\frac{1}{35} \times 37}        {Using CDF}

                         = 1 - 0.3474 = 0.6525

So, P(X > 37 min) = 1 - 0.6525 = 0.3474

Therefore, probability that the wait time is greater than 37 minutes is 0.3474.

4 0
3 years ago
Please help I don't know this and it's due today <br><br>5 - x = 12
attashe74 [19]
5 - x = 12

We're essentially just trying to get "x" onto its own side.

So, simply subtract 5 from both sides.

-x = 12 - 5

Simplify.

-x = 7

Now, divide both sides by -1.

x = -7

~Hope I helped!~
7 0
4 years ago
A spinner has three sections. The table shows the results of spinning the arrow on the spinner 80 times.
lukranit [14]
The answer is very simple.
Just divide 36 by 80. 
36/80 = .45
turn .45 into a percent.
There is a %45 chance that it will land on section 2.
4 0
3 years ago
Read 2 more answers
A home alarm system randomly assigns a five-character code for each customer. The code will not repeat a character. The characte
ahrayia [7]

Answer:

The total number of codes which can be assigned is, 55440 .

Step-by-step explanation:

According to the question, the home alarm system randomly assigns a five-character code for each customer.The code will not repeat a character and there are 11 distinct characters.

So, the total number of codes that can be randomly assigned is given by,

^{11}{P}_{5}

= \frac {11!}{6!}

= 11 \times 10 \times 9 \times 8 \times 7

= 55440

5 0
3 years ago
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