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2 years ago

How much work is done lifting a 5 kg ball from a height of 2 m to a height of 6 m? (Use 10 m/s for the acceleration

Mathematics

1 answer:

Sedbober [7]2 years ago

8 0

<h2>Explanation:</h2>

In physics, work is defined force that causes displacement. So this can be expressed by the following equation:

$W=Fs$

Where:

$F:Force \\ \\ s:Displacement$

The force can be found as:

$F=ma \\ \\ F=5(10)=50N$

And for the displacement:

$s=6-2=4m$

The force (weight) is down and the displacement is up, then the work must be negative. So:

$W=-(50)(4) \\ \\ \boxed{W=-200J}$

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Use properties of operations to determine whether 4r + 4t and 4(r+t) are equivalent. Explain your answer.

Vikki [24]

There is only one property used to determine whether

$4r+4t=4(r+t)$ .

The property is called the distributive property and in a nutshell it states, $a(b+c)=ab+ac$ , which means $a$ is distributed through $b+c$ using multiplication. So $4(r+t)$ says, distribute $4$ to $r$ and $t$ which then translates into $4r+4t$ .

4 0

2 years ago

Pls help! In the figure below, m∠ABC = 57 degrees and m∠DAB =116 degrees. What is m∠ABC?

tangare [24]

Answer:

59°

Step-by-step explanation:

116-57=59

the outside angle is the 2 inner angles added together

4 0

3 years ago

Read 2 more answers

Pls help sixowiskosixo

erma4kov [3.2K]

The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

$y = ax^2 + bx + c$

The given quadratic equation is $24x^2 + 2x = 15$

Let's rearrange the equation

$24x^2 + 2x = 15\\24x^2 + 2x - 15 = 0$

This implies that

a = 24
b = 2
c = -15

The equation or formula of quadratic formula is given as

$y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}$

We can substitute the values into the equation and solve

$y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}$