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frutty [35]
4 years ago
7

Compare the volumes of a hemisphere nd a cone with congruent bases and equal heights

Mathematics
1 answer:
Cloud [144]4 years ago
3 0
We know that
volume of a hemisphere=(1/2)*(4/3)*pi*r³----> (2/3)*pi*r³

volume of a cone=(1/3)*pi*r²*h
h=r
so
volume of a cone=(1/3)*pi*r²*r----> (1/3)*pi*r³

volume of a hemisphere/volume of a cone
= [(2/3)*pi*r³]/[(1/3)*pi*r³]
=(2/3)/(1/3)
=2
volume of a hemisphere=2*volume of a cone
<span>the volume of the hemisphere is twice the volume of the cone</span>
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julia-pushkina [17]
Hey! :)

Well, the ratio of yellow beads to blue beads is 4:5. The best way I think is to guess and check multiplying the ratio by integers. You need between 15 and 20.4 : 5 ( = 9 too little )8 : 10 ( = 18 just right)12 : 15 ( = 27 too much)So per necklace, 8 yellow beads and 10 blue beads would be needed.

Hope this helps! :)
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A survey in Men’s Health magazine reported that 39% of cardiologists said that they took vitamin E supplements. To see if this i
zzz [600]

Answer:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

Step-by-step explanation:

Information given

n=100 represent the random sample taken

X=36 represent the number of people that take E supplement

\hat p=\frac{36}{100}=0.36 estimated proportion of people who take R supplement

p_o=0.39 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is equatl to 0.39 or not, the system of hypothesis are.:  

Null hypothesis:p=0.39  

Alternative hypothesis:p \neq 0.39  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

8 0
3 years ago
A sum amount <br>to rupees 34476 in two and a half years at 4% CI. the sum is ​
Kruka [31]

Given:

Amount = Rs. 34476

Rate of compound interest = 4%

Time = 2\dfrac{1}{2}=2.5 years

To find:

The principal value.

Solution:

Formula for amount is

A=P\left(1+\dfrac{r}{100}\right)^t

Where, P is principal value, r is rate of interest and t is time in years.

Putting the given values, we  get

34476=P\left(1+\dfrac{4}{100}\right)^{2.5}

34476=P\left(1+0.04\right)^{2.5}

34476=P\left(1.04\right)^{2.5}

\dfrac{34476}{\left(1.04\right)^{2.5}}=P

Now,

P=31256.0090

P\approx 31256

Therefore, the value of sum or principal value is Rs.31256.

6 0
3 years ago
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