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Alina [70]
3 years ago
5

Raymond was riding a zip-cable from the top of a viewing post. The cable is 65 yards long. The viewing post is 52 yards high and

forms a right angle with the ground, as shown in the picture below.
Mathematics
2 answers:
grin007 [14]3 years ago
3 0
In order to figure out the horizontal distance Raymond travels using his zip cable, we may simply apply Pythagoras theorem which is, for a right triangle:
hypotenuse² = base² + height²
base = √(hypotenuse² - height²)
base = √(65² - 52²)
base =  39 yards
Raymond will travel a horizontal distance of 39 yards.
rewona [7]3 years ago
3 0

Answer:

B. 33 yards

Step-by-step explanation:

Let x represent the height of the viewing post, y represent the how far the base of the viewing post is from the end of the cable, and z represent the length of the cable. Now, use the Pythagorean theorem.

x2 + y2 = z2

(44 yd)2 + y2 = (55 yd)2

1,936 yd2 + y2 = 3,025 yd2

y2 = 1,089 yd2

y = 33 yd

So, the end of the cable is 33 yards from the base of the viewing post.

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Angela had $6w. AFter buying some books at $17 each, she had $w left.
weqwewe [10]

Answer:

Initially, Anglea has $6*w in total.

Then she buys N books, at $17 each, then the total cost of the books is: N*$17

After that, she had left $w.

a) This means that:

$6*w - N*$17 = $w

Now we can isolate the variable N in one side of the equation:

N*$17 = $6*w - $w = $5*w

N = ($5/$17)*w

N = (5/17)*w

That is the equation that tells the number of books Angela bought in terms of w.

b) Now we just need to replace the w by 34 in the above equation:

N = (5/17)*34 = 10

If w = 34, Angela bought 10 books.

5 0
3 years ago
What is the slope of a straight line that passes through points (4,2)and(6,7)?
tatiyna
\frac{7-2}{6-4} = \frac{5}{2}

The slope is the difference of the y-coordinates divided by the difference of the x-coordinates, which gives us 5/2, or 2.5


5 0
3 years ago
Please help!!! Will give Brainliest!!! A standard large pizza is cut into 10 slices. What is the sector area of one slice of lar
Aleks [24]

Answer:

See work below

Step-by-step explanation:

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5 0
3 years ago
What is the answer to this ​
asambeis [7]

-1 39/45

that is the answer

8 0
1 year ago
. Points B and G lie on ⨀O, the radius of ⨀O is 100 miles, and m∠BOG=120°. What is the approximate area of the circle segment en
Mars2501 [29]
You need the area of the sector created by the radii and the intercepted arc minus the area of the triangle created by the central angle of 120 and the segment BG.  The area of the sector is, according to our info: A= \frac{120}{360}*(3.14)(100) ^{2} which is 10466.6666.  Now we need the area of the triangle which is not as simple.  If the central angle of the whole triangle is 120, then if we split it in half and deal with right triangles only, the angle measure is now 60, and we have a 30-60-90 special right triangle.  If the hypotenuse (radius) is 100, in our pythagorean triple for that right triangle means that 100=2x and x = 50, which is going to be the side length for the side opposite the 30.  That happens to be the height of the triangle, which we need for the area.  We also need the base, which according to our Pythagorean triple, being the side across from the 60 degree angle, is 50 sqrt 3. but that's only half the side (we are still dealing with half of the whole triangle) and that means that the length of the whole side is 100 sqrt 3.  Now we can find the area of the triangle: A= \frac{1}{2}(100 \sqrt{3})(50) which is 2500 \sqrt{3}.  Now subtract the area of the triangle from the area of the sector: 10466.666-2500 \sqrt{3} =6136.5
3 0
4 years ago
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