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Ksivusya [100]
3 years ago
13

Evaluate the integral. 2 (6t i − t3 j + 2t3 k) dt 0

Mathematics
1 answer:
REY [17]3 years ago
8 0
<span>2(6ti-t3j+2t3k)dt 0= 2(6(1/2)t2i-1/4t4j+2(1/4)t4k)0 =6(1/2)(0)2i-1/4(0)4j+2(1/4)(0)4k-6(1/2)(2)2i-1/4(2)4j+2(1/4)(2)4k =-12i+4j-8k</span>
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In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ
NemiM [27]

Answer:

2.7 in²

Step-by-step explanation:

Area of ∆BAC : ∆Area of EDF = BC² : EF² (based on the area of similar triangles theorem)

Thus:

6 in^2 : x in^2 = (3 in)^2 : (2 in)^2

\frac{6}{x} = \frac{3^2}{2^2}

\frac{6}{x} = 2.25

\frac{6}{x}*x = 2.25*x

6 = 2.25x

\frac{6}{2.25} = \frac{2.25x}{2.25}

2.67 = x

Area of ∆EDF = 2.7 in²

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3 years ago
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What is a 96% confidence interval for the proportion of weight-lifting injuries in this age group that were accidental?
loris [4]
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3 years ago
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6 0
3 years ago
Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is (4 points)
lbvjy [14]

Answer:

0

Step-by-step explanation:

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3 years ago
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