What is the difference between the 7th square number and the 4th square number?

Endpoints of segment MN have coordinates (0, 0), (5, 1). The endpoints of segment AB have coordinates (1 1/22 , 2 1/4 ) and (−2

Nana76 [90]

Answer: $k=18\dfrac{8}{11}$ .

Step-by-step explanation:

If a line passing through two points, then

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

Endpoints of segment MN have coordinates (0, 0) and (5, 1).

Slope of MN $=\dfrac{1-0}{5-0}=\dfrac{1}{5}$

The endpoints of segment AB have coordinates $\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)$ and $\left(-2\dfrac{1}{4} , k\right)$ .

$A=\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)=\left(\dfrac{23}{22} ,\dfrac{9}{4}\right)$

$B=\left(-2\dfrac{1}{4} , k\right)=\left(-\dfrac{9}{4} , k\right)$ .

Slope of AB $=\dfrac{k-\frac{9}{4}}{-\frac{9}{4}-\dfrac{23}{22}}$

$=\dfrac{\frac{4k-9}{4}}{\frac{-99-46}{44}}$

$=\dfrac{4k-9}{4}\times \dfrac{44}{-145}$

$=4k-9\times \dfrac{11}{-145}$

$=\dfrac{44k-99}{-145}$

Product of slopes of two perpendicular segments is -1.

Slope of MN × Slope of AB = -1

$\dfrac{1}{5}\times \dfrac{44k-99}{-145}=-1$

$\dfrac{44k-99}{-725}=-1$

$44k-99=725$

$44k=725+99$

$k=\dfrac{824}{44}$

$k=\dfrac{206}{11}$

$k=18\dfrac{8}{11}$

Therefore, the value of k is $k=18\dfrac{8}{11}$ .

8 0

4 years ago

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Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided by 2, (b) find the critical v

babymother [125]

Answer:

We want to construct a confidence interval at 99% of confidence, so then the significance level would be $1-0.99 =0.01$ and the value of $\alpha/2 =0.005$ . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

$z_{\alpha/2}= \pm 2.576$

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

Step-by-step explanation:

For this case we have the following info given:

$\alpha=0.01, n =26, \sigma = 28.9$

We want to construct a confidence interval at 99% of confidence, so then the significance level would be $1-0.99 =0.01$ and the value of $\alpha/2 =0.005$ . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

$z_{\alpha/2}= \pm 2.576$

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

7 0

3 years ago

How many liters of pure water should be mixed with 18 liters of a12% saline solution to make a saline solution that is 3% salt?

Volgvan

Answer: .42857 liters of pure water

Step-by-step explanation:2.4 = .7w + 2.1

2.4 - 2.1 = .7w

.3 = .7w

w = .3%2F.7

3 0

3 years ago

HellpppNeed help please urgent

Novay_Z [31]

Answer:

the answer is 63.59m²

Step-by-step explanation:

$radius = \frac{diameter}{2} \\ = \frac{3}{2} \\ = \frac{9}{2} (since \:1cm = 3m \: so \: 3cm = 9m) \\ = 4.5 \\ area \: of \: circle = \pi {r}^{2} \\ = 3.14 \times (4.5) {}^{2} \\ = 3.14 \times 20.25 \\ = 63.585 {m}^{2}$

4 0

2 years ago

Find the equation of a line parallel to x=7 and passing through the point (2, -5)

Anarel [89]

Answer:

x = 2

Step-by-step explanation:

x = 7 is a vertical line parallel to the y- axis.

Thus a parallel line will also be vertical with equation

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (2, - 5) with x- coordinate 2, thus

x = 2 ← equation of parallel line

4 0

3 years ago

Read 2 more answers

What is the difference between the 7th square number and the 4th square number?​

What is the difference between the 7th square number and the 4th square number?