A genus is typically the name for a small group of closely related organisms. The second part of a scientific name, axyridis in this example, is the specific epithet. It is used to identify a particular species as separate from others belonging to the same genus.
The only possibility of the daughter being colour blind is where both parents have a recessive gene for colour blindness with the father being colour blind as well. so assuming the recessive allele is Xc, then the genotype of the mother is XCXc, where she has a normal colour vision and the father's genotype is XcY, where he is colour blind.
Answer;
-23 in males
In humans, 23 in males is the only homologous chromosome pair that isn't the same.
Explanation;
-In humans, each cell normally contains 23 pairs of chromosomes, for a total of 46.
-Twenty-two of these pairs, called autosomes, look the same in both males and females. The 23rd pair, the sex chromosomes, differ between males and females. Females have two copies of the X chromosome, while males have one X and one Y chromosome.
-The 22 autosomes are numbered by size. The other two chromosomes, X and Y, are the sex chromosomes.
The correct answer is
B. the thalamus→amygdala pathway
The neural pathway carries crude information about a threatening stimulus and activates a rapid instinctual alarm response is the thalamus→amygdala pathway
The thalamus→amygdala pathway is also known as the the path of fear. The thalamus transfers signal to other parts of the brain that causes the release of adrenaline and stress hormones.
Answer:
C) 2.0 kb
Explanation:
It is given that out of the 4 nucleotides A, T, C & G each one has equal probability to occur at any position on the DNA molecule which simply means that the probability of occurrence of any nucleotide at a position is 1/4.
Also, it is given that probability of occurrence of either A or T at 3rd position is equal which means that the probability at that particular position will be 2/4 = 1/2.
Now, GA(A/T)TC is the DNA sequence where Restriction enzyme HinfI cleaves so the total probability of an average HinfI cleavage fragment will be = 1/4 x 1/4 x 1/2 x 1/4 x 1/4 = 0.00195 = 0.2 i.e. 2 kb.
