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Simora [160]
4 years ago
15

Write an exponential function in the form y = a that goes through points ( 0 , 13 ) and ( 2 , 637 )

Mathematics
1 answer:
kiruha [24]4 years ago
4 0

Answer:

$ y = (13)7^x $

Step-by-step explanation:

When two points are given say, $ (x_1, y_1) $ and $ (x_2, y_2) $ the exponential function passing through these points is given by

                                               $ y = ab^x $

This is obtained by solving for $ a $ and $ b $ in

$ y_1 = ab^{x_1} \hspace{15mm} (1) $

$ y_2  = ab^{x_2} \hspace{15mm} (2) $

when we solve (1) and (2) for $ a $ and $ b $ we substitute it in the main equation to get the desired exponential function.

Here: $ (x_1, y_1) = (0, 13) $ and $ (x_2, y_2) = (2, 637) $.

Substituting in (1) and (2), we get:

$ 13 = ab^0 $

$ 637 = ab^2 $

From the first equation we get: $ a = 13 $  [since $ b^0 = 1 $].

Now substitute a = 13 in the second equation to get the value of b.

$ \implies 637 = (13)b^2$

$ \implies b^2 = 49 $  $ \implies b = 7 $

Substituting the values in the main equation we get:

  $  y = (13)7^x $

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