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4 years ago

15

A student model the relationship in the table with the equation x = 4y. Explain the student's error. Write and equation that cor

rectly models the relationship.

1 answer:

FrozenT [24]4 years ago

3 0

A student model relationship with equation y=4x

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What is the distance between point R (−1, 7) and point T (−7, 7) ?

zepelin [54]

You can use the distance formula to find the distance between any two points ion the plane. In this case, look carefully at the coordinates:
R(-1, 7) and T(-7, 7), Notice they both have y-coordinate 7. That means they are both on the same horizontal line. To find their distance, just subtract -7 from -1 and take the absolute value.

|-1 - (-7)| = |-1 + 7| = |6| = 6

The distance is 6 units

7 0

3 years ago

Read 2 more answers

A production plant cost-control engineer is responsible for cost reduction. One of the costly items in his plant is the amount o

Ann [662]

Answer:

248.96

Step-by-step explanation:

From this regression output we have the MS Residual or mean squared error to be equal to 61983.1

the question requires us to find the standard error of the estimate. The standard error of the estimate can be gotten by finding the square root of the MSE.

$\sqrt{61983.1}$

= 248.96

the standard error of the estimate = 248.96

thank you!

6 0

3 years ago

Find the solution to the equation z – 7 = 8.

Bas_tet [7]

Z - 7 = 8

subtract 7 from both sides

z = 15

hope this helped!

7 0

2 years ago

Read 2 more answers

Find the values of sand y <br> VR=y<br> TS=x+11<br> VT=y-3x <br> RS=x+2

Bumek [7]

I'm guessing this is a parallelogram or something, so VR=TS and RS=VT
therefore, y=x+11 and x+2=y-3x
y=x+11 , 2=y-4x
y=x+11 , y=4x+2
then use the process of elimination:
y=4x+2 then plug in: y=3+11
- y=x+11 y=14
0=3x-9 I think this is how you'd do it, tbh it's just an educated
3x=9 , x=3 guess. Btw, sorry if it looks weird

6 0

3 years ago

If you place a 89-foot ladder against the top of a 80-foot building, how many feet will

Nuetrik [128]

Answer:

$\large \boxed{\text{39 ft}}$

Step-by-step explanation:

Let x be the distance from the foot of the ladder to the base of the building.

We have a right triangle, so we can use Pythagoras' Theorem.

$\begin{array}{rcl}80^{2} + x^{2}& = & 89^{2} \\6400+ x^{2} & = & 7921\\x^{2} & = & 1521\\x & = & \sqrt{1521}\\& = &\mathbf{39}\\\end{array}\\\text{The foot of the ladder will be $\large \boxed{\textbf{39 ft}}$ from the base of the building,}$

8 0

3 years ago