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3 years ago

15

A student model the relationship in the table with the equation x = 4y. Explain the student's error. Write and equation that cor

rectly models the relationship.

1 answer:

FrozenT [24]3 years ago

3 0

A student model relationship with equation y=4x

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What are the answers I have to put in the yellow boxes?

valentinak56 [21]

The expression 1x² + 14x + 40 is a quadratic expression, and the answers in the yellow boxes are 40 and 14

<h3>How to complete the boxes?</h3>

The quadratic expression is given as:

1x² + 14x + 40

This implies that:

a = 1

b = 14

c = 40

Because a quadratic expression is represented as:

ax² + bx + c

The expressions in the yellow boxes are:

a * c and b

So, we have:

a * c = 1 * 40 = 40

b = 14

Hence, the answers in the yellow boxes are 40 and 14

Read more about quadratic expressions at:

brainly.com/question/18797214

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1 year ago

In the rectangular prism shown below, which lines are parallel?

olga_2 [115]

Answer:

JN and LP...............

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3 years ago

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g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa

adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is $\sigma = 0.0133$

Step-by-step explanation:

From the question we are told that

The upper specification is $USL = 1.68 \ mm$

The lower specification is $LSL = 1.52 \ mm$

The sample mean is $\mu = 1.6 \ mm$

The standard deviation is $\sigma = 0.03 \ mm$

Generally the capability index in mathematically represented as

$Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]$

Now what min means is that the value of CPk is the minimum between the value is the bracket

substituting value given in the question

$Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]$

=> $Cpk = min[ 0.88 , 0.88 ]$

So

$Cpk = 0.88$

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2

Now let assuming that

$\frac{\mu - LSL }{ 3 * \sigma } = 2$

So

$\frac{ 1.60 - 1.52 }{ 3 * \sigma } = 2$

=> $0.08 = 6 \sigma$

=> $\sigma = 0.0133$

So

$\frac{ 1.68 - 1.60 }{ 3 * 0.0133 }$

=> $2$

Hence

$Cpk = min[ 2, 2 ]$

So

$Cpk = 2$

So $\sigma = 0.0133$ is the value of standard deviation required

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3 years ago

Amanda exercised for 10 minutes every day in the first week, 20 minutes in the second week, 30 minutes in the third week, and 40

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Amanda's method is linear because the number of minutes increased by an equal number every week.

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2 years ago

Jen has a checking account balance that is less than -$5. Does she owe more or less than $5? Explain your answer.

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She owes more than 5 dollars because if it’s less then it won’t make sense

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2 years ago

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