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3 years ago

Please help me I just kinda got stuck on this one Thank you so much

Mathematics

2 answers:

Anon25 [30]3 years ago

8 0

To find the area of a parallelogram you do length x width, so 15•3=45 and since there is two of them multiply by 2 and get 90. Your answer is C) 90 in^2

I hoped I helped!

Anika [276]3 years ago

4 0

C 90 inches squared i took this same one

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The mult of 5-6 to the power of 76

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Step-by-step explanation:

$(5-6)^{76}=(-1)^{76}=((-1)^2)^{38}=1^{38}=\boxed{1}$

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WHAT IS THE REFERENCE ANGLE FOR 357 DEGREES

andre [41]

The reference of the angle would be 45 degrees

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3 years ago

A freight train leaves a station and travels north at 60 mph. 4 hours later, a passenger train leaves on a parallel track and t

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Answer:

first do:

60mph * 4 hours= 240mi

Let D = the distance the passenger train has to

travel to catch the freight train

Start a stopwatch when the passenger train leaves

Let t = the time on the stopwatch when they meet

Equation for freight train:

d-240=60t

Equation for passenger train:

d=100t

all together:

100t-240=60t

we can do 100t-60t because they both have (t)= 40t

40t=240 *now divide 240 by 40= 6

THEN do:

D= 100mph x 6= 600mi

They will meet 600 mi from the station

to check:

d-240=60t x 6

600-240= 360

60 x 6= 360

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3 years ago

In a recent year, a poll asked 2362 random adult citizens of a large country how they rated economic conditions. In the poll,

Harman [31]

Answer:

a) The 99% confidence interval is given by (0.198;0.242).

b) Based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

c) $\alpha=0.01$

Step-by-step explanation:

Data given and notation

n=2362 represent the random sample taken

X represent the people who says that they would watch one of the television shows.

$\hat p=\frac{X}{n}=0.22$ estimated proportion of people rated as Excellent/Good economic conditions.

$p_o=0.24$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 24% of people are rated with good economic conditions:

Null hypothesis: $p=0.24$

Alternative hypothesis: $p \neq 0.24$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a: Test the hypothesis

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np = 2362x0.22=519.64>10 and n(1-p)=2364*(1-0.22)=1843.92>10

Condition satisfied.

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.22 -0.24}{\sqrt{\frac{0.24(1-0.24)}{2362}}}=-2.28$

The confidence interval would be given by:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The critical value using $\alpha=0.01$ and $\alpha/2 =0.005$ would be $z_{\alpha/2}=2.58$ . Replacing the values given we have:

$0.22 - (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.198$

$0.22 + (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.242$

So the 99% confidence interval is given by (0.198;0.242).

Part b

Statistical decision 

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided is $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

Part c

The confidence level assumed was 99%, so then the signficance is given by $\alpha=1-confidence=1-0.99=0.01$

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3 years ago

Simplify this expression 45p - 9p + 8

beks73 [17]

Answer:

45p-9p+8 simplified is 36p+8

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