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Delvig [45]
3 years ago
12

If CE and FH are parallel lines and m<HGI are parallel lines and m<HGI = 126º, what is m<FGI? HELP ASAP​

Mathematics
1 answer:
lisov135 [29]3 years ago
6 0

Answer: <FGI = 54

Step-by-step explanation:

180-126=54

u go to agora cyber charter school?

whos ur math teacher is it  Mrs. P?

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Find the polynomial of minimum degree, with real coefficients, zeros at
drek231 [11]

Answer:

\huge\boxed{p(x)=4x^3-20x^2+4x+300}

Step-by-step explanation:

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p(x)=(x^2-2(x)(4)+4^2-3^2i^2)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ i^2=-1\\\\p(x)=(x^2-8x+16-9(-1))(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+16+9)(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+25)(x+3)\bigg(r(x)\bigg)\qquad\text{use FOIL}:\ (a+b)(c+d)=ac+ad+bc+bd\\\\p(x)=\bigg((x^2)(x)+(x^2)(3)+(-8x)(x)+(-8x)(3)+(25)(x)+(25)(3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x^3+3x^2-8x^2-24x+25x+75)\bigg(r(x)\bigg)\qquad\text{combine like terms}\\\\p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)

\text{The y-intercept is at 300}.\\\\\text{For}\ w(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+...+a_1x+a_0\\\\\text{y-intercept is}\ a_0\\\\\text{Therefore for}\ p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)\\\\\text{y-intercet is}\ 75\bigg(r(x)\bigg)\\\\75\bigg(r(x)\bigg)=300\qquad\text{divide both sides by 75}\\\\r(x)=4\\\\\text{Finally:}\\\\p(x)=(x^3-5x^2+x+75)(4)\qquad\text{use the distributive property}\\\\p(x)=(x^3)(4)+(-5x^2)(4)+(x)(4)+(75)(4)\\\\p(x)=4x^3-20x^2+4x+300

7 0
3 years ago
If y varies directly with x, and y = 2 when x = −4, what is the value of y when x = 20
Klio2033 [76]

Answer:

y = - 10

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

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To find k use the condition y = 2 when x = - 4, that is

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3 0
3 years ago
How to find minimum and maximum of this equation.
Westkost [7]

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<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

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Considering the coefficient a, we have that:

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In this problem, the equation is:

y + 4 = -x² + 1.8x

In standard format:

y = -x² + 1.8x - 4.

The coefficients are a = -1 < 0, b = 1.8, c = -4, hence the maximum value is:

y_v = -\frac{1.8^2 - 4(-1)(-4)}{4(-1)} = -3.19

More can be learned about the vertex of a quadratic function at brainly.com/question/24737967

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2 years ago
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Archy [21]

Answer:

Bruno is correct. When going from a larger unit to a smaller unit you need to divide

Step-by-step explanation:

Sam's calculation:

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Bruno's calculation:

45.7 + 40.9 + 38.0 = 124.6 miles. 124.6 divided by 0.621 = 200.64 kilometers.

1 kilometer = 0.621 miles.

Bruno is correct. When going from a larger unit to a smaller unit you need to divide

We will divide a larger value by a smaller value to get the smaller units

5 0
3 years ago
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seropon [69]

The area of the given right triangle is: 22.5 cm².

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The area of a right triangle with a base of "b" and an height of "h" can be determined using the following formula:

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Given that the right triangle has the following dimensions:

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Learn more about the area of triangle on:

brainly.com/question/21735282

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8 0
1 year ago
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