<span>What is the total interest she will pay on her loan?</span>
Answer:
The probability of selecting a family with exactly one male child is 1/4 or 0.25.
Step-by-step explanation:
Given in the question,
possible outcomes for the children's genders
{FFFF, FFFM, FFMF, FMFF, MFFF, MFFM, MFMF, MMFF, FFMM, FMFM, FMMF, FMMM, MFMM, MMFM, MMMF, MMMM}
= 16
To find,
the probability of selecting a family with exactly one male child
<h3>Probability = favourable outcomes / possible outcomes</h3>
favourable outcomes = {FFFM, FFMF, FMFF, MFFF}
= 4
Probability = 4 / 16
= 1 / 4
= 0.25
82.50?? I think because I just multiplied them.
Answer:
the quotient is 6x^2 - 16x + 16, and the remainder is just 4
Step-by-step explanation:
The polynomial 6x^3-10x^2+20 has coefficients {6, -10, 0, 20}. Division by the binomial x + 1 requires that we use -1 as the divisor. The synthetic division setup becomes:
-1 / 6 -10 0 20
-6 16 -16
-----------------------------
6 -16 16 4
Taking the coefficients {6, -16, 16}, we write the quotient as
6x^2 - 16x + 16, and the remainder as just 4.
