Given,
The sum of three integers is 92
So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"
Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)
Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,
x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17
Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51
Now,
Substituting the value of "x" in equation (2),
z = 2 (17 ) - 10
z = 34 - 10
z = 24
So, the numbers are 17, 51 and 24
NEVER HATE MATH!!!
4x-1 all u got to do is remove the parentheses and collect the like terms
Answer:
I think that the first one is not a rhombus but the last two are.
<span>We add all these numbers up.
137.50 +162.50+92.50= 392.50$
Use a cacl or by hand</span>
Answer:
Step-by-step explanation:
Let the area of water is w and area of land is l.
<u>Their ratio is:</u>
or
Find the value of l
- l = 133*3/7
- l = 57 million square miles
