Please help with this Circle Geometry question??

Mathematics

1 answer:

user100 [1]3 years ago

3 0

(i) XYZ = 180 - 64
= 116 degrees
Opposite angles in a cyclic quadrilateral add up to 180 degrees

(ii) YXZ = 23 degrees
Alternate angles in a segment are the same

(iii) OXZ = 26
XOZ = 64 x 2
= 128 degrees
The the angle at the centre is double the angle at the circumference.
180 - 128 = 52
OXZ = 52/2
= 26
Triangle OZX is an isosceles triangle

(Don't forget to include the reasons above full marks)

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But that's not what you want (although it is close).

What you want is the hypotenuse to the small lower triangle

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