Alisa says it is easier to compare the numbers in set A than the numbers in set B

2 answers:

6 0

I am not sure is this is right, but you could say that set A has a number in the millions, which makes in easier to set apart from the other one.

arlik [135]3 years ago

6 0

Numbers in Set A

1.⇒ 45,760------Five Digit Number

2.⇒1,025,680----Seven Digit Number

First number is a five digit number and Second number is Seven digit number.So, Seven Digit number is greater than five digit number.So Comparing is easy.

Set B

P: ⇒ 492,111

Q:⇒409,867

Both P and Q are Six digit numbers.So, Comparing these two numbers is Tedious.

→P >Q(As first digit is same that is 4, and unit place of Q is greater than unit place of P).

So, "Yes" Alisa's Conjecture is True.Because in Set A comparison is done between a 5 digit number and 7 Digit Number , while in set B, comparison is done between two 6 digit number.

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What’s the correct answer for this?

harkovskaia [24]

Answer:

(x + 5)² + (y - 7)² = 13

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (- 5, 7) and r = $\sqrt{13}$ , thus

(x - (- 5))² + (y - 7)² = ( $\sqrt{13}$ )² , that is

(x + 5)² + (y - 7)² = 13 ← equation of circle

4 0

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mojhsa [17]

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8 0

3 years ago

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Dmitrij [34]

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Hello!

Answer:

↓↓↓↓↓↓↓↓

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