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2 years ago

At Cassville Middle School, students can choose to study either French or Spanish. The

Mathematics

2 answers:

Semmy [17]2 years ago

8 0

<h3>Answer: French</h3>

Explanation:

The vertical bar on the inside of the box visually represents the median. For the French learners, the median is at 200. For the Spanish learners, the median is at 190.

natulia [17]2 years ago

5 0

Answer:

is french which is higher median number of learners

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Hayo! anyone speak german?<br><br><br> asking for a friend...

natali 33 [55]

Answer:sup

Step-by-step explanation:

8 0

3 years ago

This math my graduation depends on it

In-s [12.5K]

In an arithmetic sequence, consecutive terms have a fixed distance d between them. If a₁ is the first term, then

2nd term = a₂ = a₁ + d

3rd term = a₃ = a₂ + d = a₁ + 2d

4th term = a₄ = a₃ + d = a₁ + 3d

and so on, up to

nth term = $a_n = a_{n-1} + d = a_{n-2} + 2d = a_{n-3} + 3d = \cdots = a_1 + (n-1)d$

so that every term in the sequence can be expressed in terms of a₁ and d.

6. It's kind of hard to tell, but it looks like you're given a₁₃ = -53 and a₃₅ = -163.

We have

a₁₃ = a₁ + 12d = -53

a₃₅ = a₁ + 34d = -163

Solve for a₁ and d. Eliminating a₁ and solving for d gives

(a₁ + 12d) - (a₁ + 34d) = -53 - (-163)

-22d = 110

d = -5

and solving for a₁, we get

a₁ + 12•(-5) = -53

a₁ - 60 = -53

a₁ = 7

Then the nth term is recursively given by

$a_n = a_{n-1}-5$

and explicitly by

$a_n = 7 + (n-1)(-5) = 12 - 5n$

7. We do the same thing here. Use the known terms to find a₁ and d :

a₁₉ = a₁ + 18d = 15

a₃₈ = a₁ + 37d = 72

⇒ (a₁ + 18d) - (a₁ + 37d) = 15 - 72

⇒ -19d = -57

⇒ d = 3

⇒ a₁ + 18•3 = 15

⇒ a₁ = -39

Then the nth term is recursively obtained by

$a_n = a_{n-1}+3$

and explicitly by

$a_n = -39 + (n-1)\cdot3 = 3n-42$

8. I won't both reproducing the info I included in my answer to your other question about geometric sequences.

We're given that the 1st term is 3 and the 2nd term is 12, so the ratio is r = 12/3 = 4.

Then the next three terms in the sequence are

192 • 4 = 768

768 • 4 = 3072

3072 • 4 = 12,288

The recursive rule with a₁ = 3 and r = 4 is

$a_n = 4a_{n-1}$

and the explicit rule would be

$a_n = 3\cdot4^{n-1}$

7 0

2 years ago

When we use the formula for the area of a triangle, why do we use the height and not the hypotenuse?

ira [324]

Answer:

area is a half x l x h

Step-by-step explanation:

we cannot use the hypotenuse because it wouldn't bring the area

5 0

2 years ago

Read 2 more answers

Complete these ordered pairs for this equation. (0, ), (-2, ), (4, ) y=2x

quester [9]

Answer:

Part 1) The ordered pair is (0,0)

Part 2) The ordered pair is (-2,-4)

Part 3) The ordered pair is (4,8)

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem we have a direct variation

$y=2x$

Complete the ordered pairs

Part 1) we have (0,?)

For x=0

Substitute in the equation and solve for y

$y=2(0)=0$

therefore

The ordered pair is (0,0)

Part 2) we have (-2,?)

For x=-2

Substitute in the equation and solve for y

$y=2(-2)=-4$

therefore

The ordered pair is (-2,-4)

Part 3) we have (4,?)

For x=4

Substitute in the equation and solve for y

$y=2(4)=8$

therefore

The ordered pair is (4,8)

3 0

3 years ago

A box contains 8 two-inch screws. Four have a Phillips head and 4 have a slotted head. In how many ways can 4 screws be chosen s

hammer [34]

Answer:

There are $6\cdot 6=36$ different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

Step-by-step explanation:

If 4 screws must be chosen so that 2 have a Phillips head and 2 have a slotted head, then you have to choose 2 screws with a Phillips head from 4 screws with a Phillips head and 2 screws with a slotted head from 4 screws with a slotted head.

You can choose 2 screws with a Phillips head from 4 screws with a Phillips head in

$C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6$

different ways.

You can choose 2 screws with a slotted head from 4 screws with a slotted head in

$C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6$

different ways.

In total there are $6\cdot 6=36$ different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

7 0

2 years ago