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mestny [16]
3 years ago
13

Use the graph of the function to find its average rate of change from

Mathematics
1 answer:
olasank [31]3 years ago
7 0
 <span>Use the graph of the function to find its average rate of change from 
=x−3
to 
=x3 </span>is x<2\3
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2767545 to the nearest ten
vovangra [49]
276550 hope this helps !
5 0
3 years ago
Read 2 more answers
Which best describes the relationship between the lines? 2x – y = −7 2x + 4y = 2
seropon [69]

Answer:

Perpendicular

Step-by-step explanation:

2x - y = -7

2x + 4y = 2

-y = -2x - 7

4y = -2x + 2

y = 2x + 7

y = -1/2x + 1/2

Cannot be:

Parallel because the slope would otherwise be the same.

Same line because the equation is not proportional

So, they are perpendicular because a perpendicular line would be a negative and a reciprocal of the current line

8 0
3 years ago
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Please help I need it now please and thank you
Bingel [31]

Answer:

It would be the first one or second one

Step-by-step explanation:

the answer is up ahead

5 0
3 years ago
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A rectangular school banner has a length of 40 inches and a width of 24 inches. A sign is made that is similar to the school ban
e-lub [12.9K]

Answer:

The answer is 960

Step-by-step explanation:all you would have to do is multiply the lenth times width. 40x24=960  


4 0
3 years ago
2
Zigmanuir [339]

Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Step-by-step explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water  in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

6 0
2 years ago
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