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3 years ago

Can someone give me the steps to solving this equation? 3^x = 81

1 answer:

5 0

Do 81/3=27/3=9/3=3, So you see the answer is 3^4, I don't know if that's the official way to solve it but it works.

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Karen make $5 per hour babysitting and $12 per hour giving music lessons. On the weekend, she worked a total of 18 hours and mad

Lilit [14]

Answer:

11 hours

Step-by-step explanation:

Let's say Karen makes x hours babysitting and y hours giving music lessons.

Because she worked a total of 18 hours, we know that x + y = 18.

5 * x is how much money she earns babysitting for x hours, while 12 * y is how much money she earns giving music lessons for y hours. Adding them up gives her total revenue:

5x + 12y = 139

We now have a system of equations. Let's multiply both sides of x + y = 18 by 12:

12 * (x + y) = 18 * 12

12x + 12y = 216

Now, subtract 5x + 12y = 139 from 12x + 12y = 216:

12x + 12y = 216

- 5x + 12y = 139

_________________

7x + 0y = 77

Divide both sides by 7:

x = 11

Thus, Karen spent 11 hours babysitting.

4 0

2 years ago

Simplify squared 24x^5 y6

Natalka [10]

The answer is 144x^5y

Good luck

7 0

3 years ago

Read 2 more answers

In a certain country, the life expectancy of a woman born in 1995 was 80.2 years. Between 1995 and 2005, the life expectancy inc

pav-90 [236]

Answer:

que?

Step-by-step explanation:

6 0

3 years ago

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan

vitfil [10]

Answer:

$a = 6m/s^2$

Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

$a\ \alpha\ \frac{1}{m}$

Convert variation to equality

$a = \frac{F}{m}$ ; Where F is the constant of variation (Force)

Make F the subject of formula;

$F = ma$

When mass = 4kg; Acceleration = 15m/s²

$F = 4 * 15$

$F = 60N$

When mass = 10kg; Substitute 60 for Force

$F = ma$

$60 = 10 * a$

$60 = 10a$

Divide both sides by 10

$\frac{60}{10} = \frac{10a}{10}$

$a = 6m/s^2$

Hence, the acceleration is  $a = 6m/s^2$ 

4 0

3 years ago

What is 0.00078 in scientific notation?

frozen [14]

Answer: 7.8 x 10^-4

4 0

3 years ago