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svet-max [94.6K]
3 years ago
14

what is the exact value for the expression Square root 56 - Square root 14 + Square root 126 ? simplify if possible

Mathematics
1 answer:
Tasya [4]3 years ago
4 0
\sqrt{56} - \sqrt{14} +  \sqrt{126} = \sqrt{4\cdot14} - \sqrt{14} + \sqrt{9\cdot14} =\\=2 \sqrt{14} - \sqrt{14} +3 \sqrt{14} =2 \sqrt{14} - 1\sqrt{14} +3 \sqrt{14} =4 \sqrt{14}
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Describe does Glide Reflection from the preimage triangle and black to the image triangle in red
AveGali [126]

Answer:

d

Step-by-step explanation:

Lets look at V which is at (2,-4).

We will also look at it's image V' which is at (-2,-1).

Let's go through the choices:

a. translation left 4 units and down 1 unit reflection x axis

Translating V left 4 and down 1 would give us (2-4,-4-1)

(-2,-5)

Reflecting that across the x-axis would give us

(-2,5).

So this is not (-2,-1) so let's move on...

b. translation left 2 units and up 2 units reflection line x=1

Translating V left 2 and up 2 gives us

(2-2,-4+2)

(0,-2)

Now reflecting this over x=1 gives us

(2,-2). ( Imagine this x=1 which is verical going right smack between points (0,-2) and (2,-2).)

We still did not reach our goal image.

c. translation left 2 units up and up 3 units reflection y axis

Starting at V(2,-4) and moving left 2 & up 3 gives (2-2,-4+3)=(0,-1).

Now reflecting this over the vertical axis, the y-axis, gives us (0,-1).

So we did not reach our (-2,-1) point yet.

d. translation left 2 units and 3 units reflection line x=-1.

​Starting at (2,-4) then moving left 2 and up 3 gives us (2-2,-4+3)=(0,-1).

Now we are reflecting over x=-1 which means we want to choose a point on the side making x=-1 the middle. Thuis point on the other side of (0,-1) of x=-1 would be (-2,-1) which is the goal.

8 0
3 years ago
A reflection of the pink triangle is shown. Which transformation makes this reflection?
lapo4ka [179]

Answer:

The answer is A on the last question.......

Step-by-step explanation:


5 0
3 years ago
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RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

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Where:

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- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

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For the case of the given polynomial:

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We can observe that:

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\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

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lapo4ka [179]
The list of numbers from least to greatest is 

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