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2 years ago

5

They had to get 2 packages of buttons for the costume. Each package of buttons weigh 5 1/3 ounces. What is the total weight of t

he 2 packages of buttons.

1 answer:

Harrizon [31]2 years ago

3 0

Answer:

10.66 or 10 2/3

Step-by-step explanation:

2 packages

1 package weighs 5 1/3 ounces

2 x 5 1/3 = 10.66 or 10 2/3

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(2m - 5m^3 ) - (5m + 3m^3- 7m^4 ) + (8 - 3m^3- 5m^4+ 4m)

Tresset [83]

Answer:

2m^4 - 11m³ + m + 8

Step-by-step explanation:

(2m - 5m³) - (5m + 3m³ - 7m^4) + (8 - 3m³ - 5m^4 + 4m)

2m - 5m³ - 5m - 3m³ + 7m^4 + 8 - 3m³ - 5m^4 + 4m

7m^4 - 5m^4 - 5m³ - 3m³ - 3m³ + 2m - 5m + 4m + 8

2m^4 - 11m³ + m + 8

6 0

2 years ago

Read 2 more answers

What is the slope of the line that contains the points (9,-4) and (1,-5)?

marissa [1.9K]

Answer:

B

Step-by-step explanation:

6 0

2 years ago

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Leah's age is twice her cow old are Leah and her cousin?usin's age. If they add their ages together they get 36. How old are Lea

nignag [31]

Okay so lets call Leah "L" and her cousin "C". We know that L+C=36 ... we also know that Leah is twice her cousins age. Therefore, L=2 times C, or L=2C. This is because Leah's age is equivalent to twice as much as her cousin's.
Now that you know that L=2C, you can plug this back into the equation. This should make it so that's there's only one variable now!
L+C=36
(2C)+C=36 ... here we subbed in L=2C
3C=36 ... we add up the C's
C=12 ... we isolate for C by dividing both sides by 3

So her cousin's age is 12 years old. Leah's age is twice that. Thus, she's 24. If you add the two up: 12+24, you indeed get 36. Hope that helps :))

4 0

3 years ago

A professor gives her 100 students an exam; scores are normally distributed. The section has an average exam score of 80 with a

frozen [14]

Answer:

6.18% of the class has an exam score of A- or higher.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 80, \sigma = 6.5$

What percentage of the class has an exam score of A- or higher (defined as at least 90)?

This is 1 subtracted by the pvalue of Z when X = 90. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{90 - 80}{6.5}$

$Z = 1.54$

$Z = 1.54$ has a pvalue of 0.9382

1 - 0.9382 = 0.0618

6.18% of the class has an exam score of A- or higher.

4 0

2 years ago

(-2, -1), m = 3<br> I need to write it in standard form

myrzilka [38]

Answer:

$\frac{y + 1}{x + 2} = 3 \\ y + 1 = 3x + 6 \\ \color{red}y = 3x + 5$

4 0

1 year ago